Answer:
≈130.14 yards
Step-by-step explanation:
Cross Multiply
Answer:
v=26.41 m/s
Step-by-step explanation:
From the Newtons laws of motions, we sew that x= (2v₁²sin∅os∅)/g where x is the horizontal distance v is the initial speed and ∅ is the launch angle.
From trigonometry we see that 2 sin∅cos∅=sin 2∅
Therefore, x=(v²sin2∅)/g
x=22m
∅=9°
g=9.8m/s²
22m=v²×sin(2×9)/(9.8m/s²)
v²=(22×9.8)/(sin 18)
v²=697.696
v=√697.696
v=26.41 m/s
\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
In the given question, all the necessary information's are already provided. Using these information's it is easy to find the average speed of the car in miles per hour. It is given that the car covers 10 laps in 18 minutes and each lap is 3.6 miles in length.
Total distance covered by the car = (10 * 3.6) miles
= 36 miles
Now we have to convert the time from minutes to hours. So
18 minutes = 18/60 hours
= 3/10 hours
Now we can easily calculate the average speed of the favorite car of Mathew.
Average Speed = 36 * (10/3) miles/hour
= 120 miles/ hour
