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agasfer [191]
3 years ago
14

In triangle XYZ, the length of side XY is 29 mm and the length of side YZ is 43 mm. Which of the following could be the length o

f side XZ?
Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0
Be more specific. Like what is it asking you to do ? I'm trying to help. :)
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A jar contains 5 red marbles, 10 blue marbles, 1 white marble, 6 black marbles, and 3 yellow marbles. Determine the probability
Oliga [24]

Answer:

so if we make a pie chart

there's 25 marbles

it'll be 1/25 or 4% chance

a red marble is 5/ 25 or a 20% chance

say if you replace the white on the chances of you getting red will be 24% or 6/25 chance of getting red

5 0
3 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
3 years ago
an online retailer sells two packages of protein bars. (10 pack of 2.1 ounce bars for $15.37) (12 pack of 1.4 ounce bars for $15
Anna35 [415]
It is better if you purchase the 12 pack of 1.4 to point one ounce bars for 2 cents less  and get more and pay less and get more
6 0
3 years ago
Two balls are chosen randomly from an urn containing 8 white, 4 black, and 2 orange balls. Suppose that we win $2 for each black
MA_775_DIABLO [31]

Answer:

The objective of the problem is obtained below:

From the information, an urn consists of, 4 black, 2 orange balls and 8 white.

The person loses $1 for each white ball selected, no money is lost or gained for any orange balls picked and win $2 for each black ball selected. Let the random variable X denotes the winnings.

No winnings probability= 0.011

Probability of winning $1=0.3516

Probability of winning $2= 0.0879

Probability of winning $4= 0.0659

5 0
4 years ago
11 divided by 0.1595
schepotkina [342]

Answer:

68.965

Step-by-step explanation:

3 0
3 years ago
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