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3 years ago

Find the length of the arc in red shown below

Mathematics

1 answer:

Sloan [31]3 years ago

8 0

Answer:

5/4

Step-by-step explanation:

25/360=5/72

9*2=18

5/72*18=5/4

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In inches, Micah is 5 inches shorter than twice the height of Jasmine, who is 32 inches tall. How tall is Micah in inches?

Monica [59]

Micah is 5 inches shorter than twice the height of Jasmine

Micah = 5 inches shorter than 2 x Jasmine

Micah = 2 x Jasmine - 5 <em>(jasmine is 32 inches tall. Replace jasmine with 32)
</em>
Micah = 2 x 32 - 5

Micah = 64 - 5

Micah = 59

Micah is 59 inches tall

5 0

3 years ago

Read 2 more answers

Residents of a small city voted on whether to allow a developer to build a shopping center the number of votes in favor of the s

Sergeu [11.5K]

Total number of voters=4400+17600=22000

Percentage of voters in favour of the shopping center: 4400/22000=1/5=20/100=20%

Therefore, 20% of the voters are in favour of the shopping center

8 0

3 years ago

PLEASE HELP!!!!

LekaFEV [45]

Answer:

500

Step-by-step explanation:

It's a box with a square base, so let's say the width and length are x and the height is y.

The surface area of the box without the top is:

A = x² + 4xy

300 = x² + 4xy

The volume of the box is:

V = x²y

Solve for y in the first equation and substitute into the second:

y = (300 − x²) / 4x

V = x² (300 − x²) / 4x

V = x (300 − x²) / 4

V = 75x − ¼ x³

To optimize V, find dV/dx and set to 0:

dV/dx = 75 − ¾ x²

0 = 75 − ¾ x²

x = 10

So the volume of the box is:

V = 75x − ¼ x³

V = 500

The maximum volume is 500 cm³.

4 0

4 years ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

5 0

3 years ago

There are 126 Year 7 pupils in a tennis club, out of a total of 168 pupils.

Ivenika [448]

Answer:

75% of students are year 7

Step-by-step explanation:

divide 126 by 168 which equals 75% of year 7 pupils

7 0

3 years ago