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Ivahew [28]
3 years ago
6

A culture of yeast doubles in size every four hours. If the yeast population is estimated to be three million now, what will it

be one day from now? A. 96,000,000 B. 192,000,000 C. 259.000,000 D. 384,000,000
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0

Answer: B. 192,000,000

Step-by-step explanation:

The exponential growth functions in time period x is given by :-

f(x)=Ab^x, where A is the initial amount , b is the growth factor.

Given: Growth factor : b = 2

Initial population : A= 3,000,000

Time period to double in size = 4 hours

The the total number of time period in a day : \dfrac{24}{4}=6

[∵A day = 24 hours]

Then , The population of yeast after 1 day ill be :-

f(6)=3,000,000(2)^6=192,000,000

Hence, the population of yeast after 1 day =192,000,000

Bess [88]3 years ago
4 0
It doubles every 4 hours, so after 24 hours there will be 6 doublings.
2^6 = 64
So, the population will be (3,000,000 * 64) or 192,000,000 in 24 hours.
The answer is B.


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Answer:

a) 8.13

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Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

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On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

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When t = 1

R(1) = 2ln2 + 2√2

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R(12) = 2ln13 + 2√13

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R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

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R(24) = 2ln25 + 2√25

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≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

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