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Ivahew [28]
3 years ago
6

A culture of yeast doubles in size every four hours. If the yeast population is estimated to be three million now, what will it

be one day from now? A. 96,000,000 B. 192,000,000 C. 259.000,000 D. 384,000,000
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0

Answer: B. 192,000,000

Step-by-step explanation:

The exponential growth functions in time period x is given by :-

f(x)=Ab^x, where A is the initial amount , b is the growth factor.

Given: Growth factor : b = 2

Initial population : A= 3,000,000

Time period to double in size = 4 hours

The the total number of time period in a day : \dfrac{24}{4}=6

[∵A day = 24 hours]

Then , The population of yeast after 1 day ill be :-

f(6)=3,000,000(2)^6=192,000,000

Hence, the population of yeast after 1 day =192,000,000

Bess [88]3 years ago
4 0
It doubles every 4 hours, so after 24 hours there will be 6 doublings.
2^6 = 64
So, the population will be (3,000,000 * 64) or 192,000,000 in 24 hours.
The answer is B.


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1 year ago
Let the abbreviation PSLT stand for the percent of the gross family income that goes into paying state and local taxes. Suppose
gavmur [86]

Answer:

Number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.

Step-by-step explanation:

We are given that one wants to estimate the mean PSLT for the population of all families in New York City with gross incomes in the range $35.000 to $40.000.

If sigma equals 2.0, we have to find that how many families should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5.

Here, we will use the concept of Margin of error as the statement "true mean PSLT within 0.5" represents the margin of error we want.

<u></u>

<u>SO, Margin of error formula is given by;</u>

       Margin of error =  Z_(_\frac{\alpha}{2}_ ) \times \frac{\sigma}{\sqrt{n} }

where, \alpha = significance level = 10%

            \sigma = standard deviation = 2.0

            n = number of families

Now, in the z table the critical value of x at 5% ( \frac{0.10}{2} = 0.05 ) level of significance is 1.645.

SO,        Margin of error =  Z_(_\frac{\alpha}{2}_ ) \times \frac{\sigma}{\sqrt{n} }

                          0.5   =  1.645 \times \frac{2}{\sqrt{n} }

                         \sqrt{n} =\frac{2\times 1.645 }{0.5}

                         \sqrt{n} =6.58

                           n  =  6.58^{2}

                               = 43.3 ≈ 43

Therefore, number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.

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3 years ago
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