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N76 [4]
3 years ago
14

Drinking 8 fluid ounces of milk provides 270.0 milligrams of calcium. How many fluid ounces of milk provide 72.5 milligrams of c

alcium? Round to the nearest tenth.

Mathematics
2 answers:
Serga [27]3 years ago
8 0
Heya !

Check the attachment.
Hope it helps you :)

Margarita [4]3 years ago
3 0
Set up a proportion:

\frac{8}{270} = \frac{x}{72.5}

The numerator represents fluid ounces of milk, and the denominator represents milligrams of calcium.

Simplify the first fraction to make multiplication easier:

\frac{8}{270} \div  \frac{2}{2} =  \frac{4}{135}
\frac{4}{135} = \frac{x}{72.5}

Cross multiply the fractions:

72.5 * 4 = 290
135x = 290

Divide both sides by 135 to get x by itself:

290 \div 135 = 2.1
x = 2.1


2.1 fluid ounces of milk provide 72.5 milligrams of calcium.
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Since he drives 60 miles per hour we'll divide 272 by 60

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I hope I've helped!
6 0
3 years ago
The following sample of weights was taken from 8 cookies off the assembly line. Construct the 95% confidence interval for the po
Gemiola [76]

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what are you asking

Step-by-step explanation:

8 0
3 years ago
At a benefit​ concert, fifteen bands have volunteered to perform but there is only enough time for five of the bands to play. Ho
Iteru [2.4K]

Answer:

360,360

Step-by-step explanation:

So we only have 5 spots, but 15 bands to fill those spots.

For the first spot, we can choose from any of the 15 bands, so we have 15 choices.

For the second spot, we can choose from the 14 remaining bands (because we already chose one for the first spot), so we have 14 choices.

For the third spot, by similar reasoning as above, we have 13 choices; for the fourth spot, 12 choices; and for the last spot, we have 11 choices.

We realize that for each of the 15 possible bands in the first spot, we still have 14 possible bands for the second spot, and so on. Thus, we know to multiply instead of add.

Our answer is: 15 * 14 * 13 * 12 * 11 = 360,360

6 0
4 years ago
According to a recent​ survey, the population distribution of number of years of education for​ self-employed individuals in a c
creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean \mu and standard deviation \sigma, then the distribution of sample mean will be normally distributed with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

b) mean and the standard for a random sample of size 49

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4

c) mean and the standard for a random sample of size 196

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0
3 years ago
Simplify.<br><br> 5x+3(x+2)+3<br><br><br> 6x + 8<br><br> 8x + 9<br><br> 8x + 5<br><br> 5x + 8
beks73 [17]

\\ \sf\longmapsto 5x+3(x+2)+3

\\ \sf\longmapsto 5x+3x+6+3

\\ \sf\longmapsto (5+3)x+9

\\ \sf\longmapsto 8x+9

7 0
3 years ago
Read 2 more answers
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