(m+4)(m+1)
=m^2+5m+4........
Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠ 
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Step-by-step explanation:
So, in order to rationalize the denominator, we need to get rid of all radicals that are in the denominator.
Step 1: Multiply numerator and denominator by a radical that will get rid of the radical in the denominator. ...
Step 2: Make sure all radicals are simplified. ...
Step 3: Simplify the fraction if needed.
Answer:
y = 96°
Step-by-step explanation:
The measure of the inscribed angle y is half the measure of its intercepted arc.
The whole circle = 360°
the intercepted arc = 360° - 168° = 192°
Thus
y =
× 192° = 96°