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Find the mean absolutedeviation of the set of data.2, 4, 5, 5, 3
1 answer:
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Answer:
(-5,9+√8)
Step-by-step explanation:
There are two ways in which you can find a point that lies in the circle. One of them is to do y the subject of the formula, and another one is to determine the center of the circumference, and with the information of the radius, you can sum this value upward or downward.
the general equation of a circle is:
with center at (h,k)
you have the following equation:
Then, the center is (-5,9)
if you sum the value of the radius in one of the fourth directions (up, down, left, right), for example upward you have
Then, one point that lies in the circle is (-5,9+√8)
Answer:
We conclude that the initial value and y-intercept are the same thing on a graph.
Please check the attached graph of the equation y = 2x+1.
Step-by-step explanation:
We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.
In other words, the initial value is the y-value or output of the point at x = 0
For example,
Let the equation
y = 2x+1
substitute x = 0
y = 2(0)+1
y = 0+1
y = 1
Thus, the initial value of the equation y = 2x+1 is: y = 1
Please check the attached graph of the equation y = 2x+1.
It is clear from the graph that at x = 0, the value of y = 1.
Thus, at y = 1, the line meets the y-axis.
Hence, the initial value of the line is: y = 1
Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
For example,
Let the equation
y = 2x+1
substitute x = 0
y = 2(0)+1
y = 0+1
y = 1
Thus, the y-intercept of y = 2x+1 is y = 1.
Please check the attached graph of the equation y = 2x+1.
It is clear from the graph that at x = 0, the value of y = 1.
Therefore, the y-intercept of y = 2x+1 is y = 1.
Conclusion:
Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.
Please check the attached graph of the equation y = 2x+1.
