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2 years ago

1/3 x 3/4 Help me plss

Mathematics

2 answers:

EastWind [94]2 years ago

8 0

Answer:

1/4

Step-by-step explanation:

this should be it

(hope it helps)

zmey [24]2 years ago

4 0

Answer:

1/4 is your answer.....

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An exterior angle of an isosceles triangle has measure 130°. Find two possible sets of measures for the angles of the triangle.

frozen [14]

(1) it can be both exterior of vertex or base. 180-130=50°
vertex is 50°: base=(180-50)/2=65°
base is 50°: vertex= 180-2*50=80°

vertex 50 base 65; vertex 80, base 50

(2)base=180-130=50°
vertex=180-2*50=80°

base 50 vertex 80

5 0

2 years ago

What is the absolute value of -3+4i

Pavlova-9 [17]

$|-3+4i|=\sqrt{(-3)^2+4^2}=\sqrt{25}=5$

7 0

3 years ago

Read 2 more answers

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$

Here n = 6

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{1 * 12376}{38760}]$

$P(X \ge 1) =1- 0.3193$

$P(X \ge 1) = 0.6807$

5 0

3 years ago

A can of hairspray has a

lara [203]

Answer:

2inches=5.08cm

TSA of cylinder=2πr(r+h)

2×22/7×5.08(5.08+5.08)

6×5.08×10.16

324.42cm^3

7 0

1 year ago

5x-y=7

seropon [69]

Answer:

see graph of y = 5x - 7

Step-by-step explanation:

If graphing is the task, you should rewrite the equation in a y = ax + b form. All straight lines can be described in this form, only the a and b determine which line it is.

Your equation 5x-y=7 has the 5x on the left side, so lets move it to the right. It will get a negative sign (this is the same as subtracting 5x like you did in your picture)

5x - y = 7

-y = 7 - 5x

Now we still have the -y which should be a +y. So we multiply left and right with -1 and get:

y = -7 + 5x

If we swap the -y and 5x (we can, because they are just an addition), we get:

y = 5x - 7

Now the equation is in its "normal" form. It's like the y = ax + b with a and b chosen as a=5 and b=-7.

The normal form is handy because you can immediately see the slope is 5 and the intersection with the y-axis is at y=-7.

3 0

3 years ago