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2 years ago

I reallllyy neeeeedd helpppp dont be capping put the right answer

Mathematics

1 answer:

Jlenok [28]2 years ago

7 0

I believe it's A, C and D.

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An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

2 years ago

What is an expression to represent the equation

Tatiana [17]

Answer:

8 + $\frac{x}{4}$

Step-by-step explanation:

I'm assuming you want an answer to the top section of the question.

We can start with 8.

When a problem asks for the sum, it's looking for addition, so we use the + sign.

8 +

The problem says "a number," so let's represent that with x. Basically, x just means a number we don't know.

8 + x

The "number" is divided by 4, so we'll just put x/4 as our second term.

8 + $\frac{x}{4}$

7 0

3 years ago

Simplify ..............

larisa86 [58]

Answer:

The third response

Step-by-step explanation:

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2 years ago

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Fofino [41]

$Domain:x\neq-3\\\\\dfrac{2x}{x+3}\leq3\qquad\text{subtract 3 from both sides}\\\\\dfrac{2x}{x+3}-3\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3(x+3)}{x+3}\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3x+9}{x+3}\leq0\\\\\dfrac{2x-(3x+9)}{x+3}\leq0\\\\\dfrac{2x-3x-9}{x+3}\leq0\\\\\dfrac{-x-9}{x+3}\leq0\Rightarrow(x+3)(-x-9)\leq0\\\\x=-3,\ x=-9\\\\x\in(-\infty,\ -9]\ \cup\ (-3,\ \infty)$

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3 years ago

The region r is bounded by the parabola y = x2 and the line y = 4. set up definite integrals to find the moment mx of r about th

nikklg [1K]

Consider this option:
Volume is 256π/5, area is 32/3.
Details are in the attachment.
P.S. intersection points are (-2;4) and (2;4).

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3 years ago