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marta [7]
3 years ago
9

Consider a population of size N = 100 with the three individual mutants with relative growth rate rA = 2, rB = 1.01, and rC = 0.

99. What is the probability that each of the three mutants will take over the population?
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer 1 / 25

Step-by-step explanation:

The probability that the first

of the three mutants will take over the population = 2 / 100

The probability that the second

of the three mutants will take over the population = 1.01 / 100

The probability that the third

of the three mutants will take over the population = 0.99 / 100

Therefore, the probability that each of the three mutants will take over the population = probability of the first,second or third = 2 / 100 + 1.01 / 100 + 0.99 / 100 = (2+1.01+0.99)/100 = 4 / 100 = 2/25

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Rafael want to buy the same number of gifts bags and bows gifts bags are sold in packs of 6. Bows are sold in packs of 9. What i
GenaCL600 [577]

Answer:

Rafael should buy 9 gift bags and 6 bows packet so, that she can have SAME NUMBER OF ITEMS, i.e 54.

Step-by-step explanation:

The gift bags are sold in the packs of 6.

So, the number of gift bags in 1 packet  = 6 gift bags

The number of gift bags in 2  packet  = 6 x 2 gift bags  = 12  gift bags

The number of gift bags in 3  packet  = 6 x 3 gift bags  = 18  gift bags

And continuing similarly, we get

The number of gift bags in 9  packet  = 6 x 9 gift bags  = 54 gift bags.. (1)

The bows are sold in the pack of 9.

So, the number of bows in 1 packet  = 9 bows

The number of bows in 2 packet   = 9 x 2 bows  = 18 bows

The number of bows in 3 packet   = 9 x 3 bows  = 27 bows

And continuing similarly, we get

The number of bows in 6  packet  = 9 x 6 bows  = 54 bows... (2)

Here, comparing both equations (1) and (2) , we get

The number of gift bags = 54  = The number of bows.

Hence, Rafael should buy 9 gift bags and 6 packet of bows so, that she can have SAME NUMBER OF ITEMS, i.e 54.

8 0
3 years ago
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kow [346]

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Step by Step explanation:

4 0
3 years ago
What is this equation x2 – 2x – 6 in vertex form?
Lena [83]

Answer:

In vertex form, the parabola's equation is y=(x−1)^2 +5.

Step-by-step explanation:

7 0
3 years ago
Select all of the following that are quadratic equations.
goldenfox [79]

Answer:

1. x² + 3x - 5 = 0

2. x² - x = 3 x + 7

4. 7x² + 14x = 0

Step-by-step explanation:

A Quadratic equation takes the form;

ax² + bx + c = 0

a, b, c are constants and a cannot be 0.

Options 1 fits this;

x² + 3x - 5 = 0

Option 2 fits this as well;

x² - x = 3 x + 7  

x² -x - 3x - 7 = 0

x² - 4x - 7 = 0

Option 4 fits this as well if c = 0.

7x² + 14x + 0 = 0

8 0
3 years ago
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
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