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3 years ago

6

25 POINTS!!!!!!!!!!!!

1 answer:

mario62 [17]3 years ago

4 0

Hi kiddo!

So these equations can be pretty tricky, but I’m happy to help.

What we want to do first is move all the terms to the left side and set equal to zero. Then after that step you should set each factor equal to zero. After these steps and calculations you get...

D= 4/5b-h
Choose choice D

^There we have it!^
I hope this completely answers your question.
~Brooke❤️

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Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

$P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}$

$P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}$

$P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}$

The expected number of men in the delegation is

$E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)$

$E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}$

$E(x)=\dfrac{6}{7}$

$E(x)\approx 0.86$

Therefore, the expected number of men in the delegation is 0.86.

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_____________________

a(6,-7) m(7,-5) letb(p,q)

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Step-by-step explanation:

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