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aleksandrvk [35]
3 years ago
10

Which group is in order from least to greatest magnitude?

Mathematics
2 answers:
ipn [44]3 years ago
8 0

Answer:

Which group is in order from least to greatest magnitude?

Negative 5 and one-third, –2, 1.4, 4, 6

<h2>1.4, –2, 4, Negative 5 and one-third, 6</h2>

6, Negative 5 and one-third, 4, –2, 1.4

–2, Negative 5 and one-third, 1.4, 4, 6

B is the answer!

saveliy_v [14]3 years ago
4 0

Answer is B

Step-by-step explanation:

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D

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D

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Hey ,the last one 2*2*2*3*5*5+2*2*2*2*2=8*3*25+36=600+36=636

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What is the value of x in the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7Dx%20-%5Cfrac%7B2%7D%7B3%7D" id="Te
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Answer:

x= 200

Step-by-step explanation:

The given equation is:

1/5 x - 2/3 y = 30

The value of y is 15

Put the value of y in the given equation:

1/5 x - 2/3(15) = 30

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Take the L.C.M of the denominator

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Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis
Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

f(x)=6

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

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f(x)=-3

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

f(x)=1

Therefore the graph represents a piecewise function, which is defined as

f(x)=\begin{cases}6& \text{ if } x2 \end{cases}

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

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6\neq-3

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

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3 years ago
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