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astra-53 [7]
4 years ago
10

C=zn+z solve for n please help me

Mathematics
1 answer:
worty [1.4K]4 years ago
8 0

Answer:

n = c/z

Step-by-step explanation:

c = zn + z

c/z = zn/z + z/z (Divide all terms by z)

c/z = n + z/z (Simplify)

c/z = n (Simplify further/answer)

Hope this helps :)

Mark as Brainliest if it was please

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Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
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Answer:

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3 years ago
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Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin
Sidana [21]

Answer:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean \bar X is given by:

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\mu_{\bar X} = \mu

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \mu

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How many solutions do consistent dependent lines have
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The length of Dwight's garden is 12.5 meters. Dwight measured it but made a measurement error of 6%. Find the lowest and highest
pishuonlain [190]

Answer: See Explanation

Step-by-step explanation:

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= 12.5 - (0.06 × 12.5)

= 12.5 - 0.75

= 11.75 meters

The lowest measurement Dwight could have made will be:

= 12.5 + (6% × 12.5)

= 12.5 + (0.06 × 12.5)

= 12.5 + 0.75

= 13.25 meters

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