You first must find the 18% of the fish population.
You multiply 500 by .18 . You are supposed to get 90.
90 is the 18% fish increase.
Then you just add 500 + 90 and you will get 590 fish that are now in the school.
Answer:
2.5 or 250.
Step-by-step explanation:
Answer:
this will help https://www.google.com/search?q=factoring+equations&oq=factoring+equations&aqs=chrome..69i57j0l6j69i61.464j0j7&sourceid=chrome&ie=UTF-8#kpvalbx=_w9Z8XvnVCsq7tgXx3SM51
Step-by-step explanation:
its in the video https://www.google.com/search?q=factoring+equations&oq=factoring+equations&aqs=chrome..69i57j0l6j69i61.464j0j7&sourceid=chrome&ie=UTF-8#kpvalbx=_w9Z8XvnVCsq7tgXx3SM51
Step-by-step explanation:
∫₀³⁰ (r/V C₀ e^(-rt/V)) dt
If u = -rt/V, then du = -r/V dt.
∫ -C₀ e^u du
-C₀ ∫ e^u du
-C₀ e^u + C
-C₀ e^(-rt/V) + C
Evaluate between t=0 and t=30.
-C₀ e^(-30r/V) − -C₀ e^(-0r/V)
-C₀ e^(-30r/V) + C₀
C₀ (-e^(-30r/V) + 1)
I got the same answer. Try changing the lowercase v to an uppercase V.
