Answer:
The % of children with webbed digits is
%
Explanation:
Given -
Syndactyly or webbed digits are due to the presence of a dominant allele (S). Then the allele for normal digits would be represented by allele "s"
A normal man with normal digits and genotype "ss" marries a woman with webbed digits and has a hetrozygous genotype i.e "Ss"
If we cross Ss and ss , then the following offspring are produced -
Ss * ss
Ss, Ss, ss, ss
Out of four 2 offspring with genotype ss have normal digits and remaining two offspring with genotype "Ss" have webbed digits. Thus, the % of children with webbed digits is
%
Answer: D
Explanation:
Because the heavy plow and its traction team was expensive tool and individual peasant farmers were not able to own it, it brought collective ownership and patterns of communal agriculture and communal animal husbandry.
The heavy plough required more energy to pull this resulted several families coming together to pool their oxen to form a team large and strong enough to pull the heavy plow. The resulting “ox-gangs” became an important social group.
Answer: D. It yields chromosomes that contain both maternal and paternal DNA.
Explanation:
The recombination or crossing over is a genetic process. It takes place during the Prophase I of meiosis. The homologous pair align and held together by synapsis. This results in the mixture of genes combination formed from both parents that can be represented as a single chromosome.
If the recombination do not occur then each chromosome will be either 100% maternal or paternal. Thus recombination assures the recombinant chromosomes which consists of genetic material from both parents. Thus the genetic diversity of offspring increases.
I have no clue i never learned this also never learned common core