Answer:
CI ≈ (173.8 < μ < 196.2)
Step-by-step explanation:
We are told that laboratory tested twelve chicken eggs. Thus;
n = 12
Mean; x¯ = 185 mg
S.D; s = 17.6 mg
DF = n - 1 = 12 - 1 = 11
We have a 95% confidence level. Thus; α = 0.05
Since n < 30, we will use t-sample test.
Thus, from t-table attached at 95% Confidence level and DF = 11, we have;
t = 2.201
Thus,formula for Confidence interval is;
CI = (x¯ - t(s/√n)) < μ < (x¯ + t(s/√n))
CI = (185 - 2.201(17.6/√12)) < μ < (185 + 2.201(17.6/√12))
CI = (185 - 11.1825) < μ < (185 + 11.1825)
CI = (173.8175 < μ < 196.1825)
CI ≈ (173.8 < μ < 196.2)
Answer: the exact perimeter of the figure is 53.68 cm
Step-by-step explanation:
The angle formed by the shaded sector is
360 - 90 = 270 degrees
We would determine the length of the arc formed by the shaded portion by applying the formula for length of arc which is expressed as
Length of arc = θ/360 × 2πr
Where
θ represents the central angle.
r represents the radius of the circle.
π is a constant whose value is 3.14
From the information given,
Radius, r = 8 cm
θ = 270 degrees
Length of arc = 270/360 × 2 × 3.14 × 8
= 37.68 cm
Perimeter of the figure is
Length of arc + radius + radius
It becomes
37.68 + 8 + 8 = 53.68 cm
Answer:
<em> f ( x ) = - 2x^2 + 3x + 1</em>
Step-by-step explanation:
If f (x ) extends to → − ∞, as x→ − ∞ , provided f(x) → − ∞, as x → +∞, we can rewrite this representation as such;
− ∞ < x < ∞, while y > − ∞
Now the simplest representation of this parabola is f ( x ) = - x^2, provided it is a down - facing parabola;
If we are considering a down - facing parabola, the degree of this trinomial we should create should be even, the LCM being negative. Knowing that we can consider this equation;
<em>Solution; f ( x ) = - 2x^2 + 3x + 1</em>, where the degree is 2, the LCM ⇒ - 2
Answer:
1.4
Step-by-step explanation:
Step-by-step explanation:
Assume that
hence,
now,
attached below is the complete solution
