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4 years ago

The length of the leg of right isosceles triangle is a. Find the length of the hypotenuse.

1 answer:

6 0

A right isosceles triangle has two 45 degree angles. This means the side lengths are the same, so if one leg is a, the other leg is also a.

The hypotenuse of an isosceles triangle is the length os a leg multiplied by the square root of 2.

The hypotenuse would be: a√2

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A restaurant bill comes to 39.24 fine the total when tax is 7% and tip is 15%

xz_007 [3.2K]

Answer:

hjv j

Step-by-step explanation:

kkj

8 0

3 years ago

Rachel has taken 6 tests so far and has received scores of 83%, 92%, 79%, 88%, 89%, and 95%. What must Rachel receive on her sev

Vinil7 [7]

Let the score on her seventh test be "x".

SO,

$\frac{83+92+79+88+89+95+x}{7} =90\\\\ \frac{526+x}{7}=90\\\\ 526+x=630\\\\x=630-526\\\\ \boxed{x=104}$

∴ He must get 104% on his seventh test to get an average score of 90%

5 0

3 years ago

Read 2 more answers

Match each expression with an equivalent expression.

Marysya12 [62]

Answer:

$6x-4y$ → 4. $2(3x-2y)$

$6-4x$ → 3. $2(3-2x)$

$6x-4x$ → 1. $2x$

$6x-4$ → 2. $2(3x-2)$

Step-by-step explanation:

You need to:

Factor out 2 from $6x-4y$ , then you get the equivalent expression:

$=2(3x-2y)$ this matches with OPTION 4

Factor out 2 from $6-4y$ , then you get the equivalent expression:

$=2(3-2x)$ this matches with OPTION 3

Make the subtraction for $6x-4x$ , then you get the equivalent expression:

$=2x$ this matches with OPTION 1

Factor out 2 from $6x-4$ , then you get the equivalent expression:

$=2(3x-2)$ this matches with OPTION 2

3 0

3 years ago

Read 2 more answers

A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?

zzz [600]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf 240 \: {inches}^{2} }}}}$

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

First, finding the width of a rectangle

$\boxed{ \sf{perimeter = 2(l + w)}}$

plug the values

⇒ $\sf{64 = 2(20 + w)}$

Distribute 2 through the parentheses

⇒ $\sf{64 = 40 + 2w}$

Swap the sides of the equation

⇒ $\sf{40 + 2w = 64}$

Move 2w to right hand side and change it's sign

⇒ $\sf{2w = 64 - 40}$

Subtract 40 from 64

⇒ $\sf{2w = 24}$

Divide both sides of the equation by 2

⇒ $\sf{ \frac{2w}{2} = \frac{24}{2} }$

Calculate

⇒ $\sf{w = 12 \: inches}$

Width of a rectangle ( w ) = 12 inches

Now, finding the area of a rectangle having length of 20 inches and width of 12 inches

$\boxed{ \sf{area \: of \: rectangle = length \: \times \: \: width}}$

plug the values

⇒ $\sf{area \: of \: rectangle =20 \times 12 }$

Multiply the numbers : 20 and 12

⇒ $\sf{area \: of \: rectangle = 240 \: {inches}^{2} }$

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

7 0

3 years ago

Suppose that you can only use the set of small letters characters (a-z) and odd numbers (1, 3, 5, 7, 9) to set a password. What

Flauer [41]

Answer:

$31^8$

Step-by-step explanation:

To create a password, you need to select 8 characters (not necessarily different) from the set {1,3,5,7,9,a,b,c,...,z}. Now, this set has 31 elements: the 26 lowercase letters from the alphabet and the 5 odd numbers (1,3,5,7,9).

Now, there are 31 ways to choose the first character, it can be any element from our set. The second character can also be chosen in 31 ways, because there are not restrictions (repetitions, specific characters, etc). Similarly, the third, fourth, fifth, sixth, seventh and eighth characters have 31 possibilities each one.

The number of passwords is the number of ways of selecting the 8 characters, then by the multiplication principle the number of passwords is 31×31×31×31×31×31×31×31=31^8.

6 0

4 years ago