gg easy
we want to cancel 1 term
first, get them into form am+bn=c where a, b, and c are constants
m-2n=2 is good
m+n=2(n-3) is m+n=2n-6 which is m-n=-6
compare constants
m's have 1 and 1
n's have -2 and -1
let's cancel m's
a. multiply 1st equation by -1
-m+2n=-2
add to 2nd equation
-m+2n=-2
<u>m-n=-6 +</u>
0m+n=-8
n=-8
sub back
m-n=-6
m-(-8)=-6
m+8=-6
m=-14
b. to check
m=-14 and n=-8
m-2n=2
-14-2(-8)=2
-14+16=2
2=2 yep
m-n=-6
-14-(-8)=-6
-14+8=-6
-6=-6 yep
so m=-14 and n=-8 is the solution
Since the solution cannot be negative hence the true solution to the expression is x = 10
<h3>Laws of logarithm</h3>
Given the logarithmic expression
ln 20 + ln 5 = 2lnx
In logarithmic law, the sum of log is equivalent to its product .The equation above can be written as:
ln(20*5) = 2lnx
ln100 =2lnx
ln100 = lnx^2
x^2 =100
x = 10
Since the solution cannot be negative hence the true solution to the expression is x = 10
Learn more on log functions here: brainly.com/question/13473114
Answer:
multiply x through out:
factorise out x²:
take square root on both sides:
