All categories

3 years ago

Find the LCM of 91, 143 and 169

Mathematics

2 answers:

lidiya [134]3 years ago

8 0

91 = 7×13

143 = 11×13

169 = 13²

LCM = 7×11×13² = 77×169 = 13013

Allushta [10]3 years ago

7 0

Answer:

13013

Step-by-step explanation:

Express each number in terms of the product of prime numbers.

91 = 7 × 13

143 = 11 × 13

169 = 13 × 13

Now consider the maximum number of times each factor occurs for each number.

The factor 7 occurs once

The factor 11 occurs once

The factor 13 is repeated twice ( maximum number of times for 1 number )

Thus LCM = 7 × 11 × 13 × 13 = 13013

You might be interested in

oel biked 9 miles east and then 12 miles north. If he biked back to his starting point using the most direct route, how many mil

kvasek [131]

Answer:

36 miles

Step-by-step explanation:

(Imagine a huge triangle on a perfectly open space-- not with streets or houses or cornfields.)

The dimensions of the two sides given are multiples of a classic Pythagorean Triple: 3, 4, 5. $3^{2} + 4^{2} = 5^{2}$

9 is 3x3, 12 is 3x4 so the remaining side would be 3x5 15

Add those 3 sides to get the total distance, 36 miles.

6 0

3 years ago

Please awnser this asap

Illusion [34]

Answer:

Base area = 25.2 in^2

Step-by-step explanation:

Base area = 63/2.5 = 25.2 in^2

8 0

2 years ago

Which classification correctly describes the polygon?

sergiy2304 [10]

Answer is (A) because it is concave and it has 8 sides

5 0

2 years ago

What’s the answer to 2(4+9w)

maks197457 [2]

Answer:

8+18W

Step-by-step explanation:

distribute the 2 into the parentheses. 2×4 is 8 and 2×8 is 18.

3 0

3 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

Addition:

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

Multiplication:

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

3 years ago

Find the LCM of 91, 143 and 169​

Find the LCM of 91, 143 and 169