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KatRina [158]
3 years ago
8

Helppppp..... evaluate 3^-3=

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

For this case we must evaluate the following expression:

3 ^ {3}

We have by definition of properties of powers that:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

Then, rewriting the expression:

3 ^ {- 3} = \frac {1} {3 ^ 3} = \frac {1} {27}

ANswer:

3 ^ {- 3} = \frac {1} {27}

OptionB

elixir [45]3 years ago
6 0

ANSWER

The answer is

B

\frac{1}{27}

EXPLANATION

The given expression is

{3}^{ - 3}

Use the negative index property;

{a}^{ - m}  =  \frac{1}{ {a}^{m} }

We apply this property to get:

{3}^{ - 3}  =  \frac{1}{ {3}^{3} }

This gives us:

{3}^{ - 3}  =  \frac{1}{3 \times 3 \times 3 }

{3}^{ - 3}  =  \frac{1}{27}

The correct option is B.

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<h3>What will be the value of x?</h3>

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First off, you can rewrite your equation like so: c=(a-b)x. You can then plug in your given constraints for your choices. If a-b = 1 and c = 0 leaving: 0=1(x), x must equal 0 and only 0 as any constant multiplied by 0 equals 0. So that choice is eliminated. Now let's consider when a=b and c != 0. Since we are given a-b and a=b and c != 0, we have:
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