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KatRina [158]
2 years ago
8

Helppppp..... evaluate 3^-3=

Mathematics
2 answers:
MrRa [10]2 years ago
8 0

For this case we must evaluate the following expression:

3 ^ {3}

We have by definition of properties of powers that:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

Then, rewriting the expression:

3 ^ {- 3} = \frac {1} {3 ^ 3} = \frac {1} {27}

ANswer:

3 ^ {- 3} = \frac {1} {27}

OptionB

elixir [45]2 years ago
6 0

ANSWER

The answer is

B

\frac{1}{27}

EXPLANATION

The given expression is

{3}^{ - 3}

Use the negative index property;

{a}^{ - m}  =  \frac{1}{ {a}^{m} }

We apply this property to get:

{3}^{ - 3}  =  \frac{1}{ {3}^{3} }

This gives us:

{3}^{ - 3}  =  \frac{1}{3 \times 3 \times 3 }

{3}^{ - 3}  =  \frac{1}{27}

The correct option is B.

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Answer:

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Step-by-step explanation:

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From the start, since we have a variable in the exponent, we can recognize that it's exponential. Figuring out growth or decay is a little more complicated. Having a negative sign out front can flip the graph; having a negative sign in the exponent flips the graph, too. In your case, you have no negatives; just 2(1/2)^x. What you need to note here, and you could use a few test points to check, is that as x gets bigger, (1/2) will get smaller and smaller. Think about it. When x = 0, 2(1/2)^0 simplifies to just 2. When x = 1, 2(1/2)^1 simplifies to 1. Already, we can tell that this graph is declining, but if you want to make sure, try a really big value for x, like 100. 2(1/2)^100 is a value very very very veeery close to 0. Therefore, you can tell that as the exponent gets larger, the value of the function goes down and gets closer and closer to zero. This means that it can't be exponential growth. In the case of exponential growth, as the exponent gets bigger, your output should increase, too.

3 0
3 years ago
-x^(2)-12=-87<br><br> Please explain your answer, and how I make the x positive
spayn [35]
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