Answer:
Therefore, the volume of the cone is V=4π.
Step-by-step explanation:
From task we have a circular cone with radius 2 m and height 3 m. We use the disk method to find the volume of this cone.
We have the formula:
We know that r=2 and h=3, and we get:
![V=\int_0^3\pi \cdot \left(\frac{2}{3}x\right)^2\, dx\\\\V=\int_0^3 \pi \frac{4}{9}x^2\, dx\\\\V= \frac{4\pi}{9} \int_0^3 x^2\, dx\\\\V= \frac{4\pi}{9} \left[\frac{x^3}{3}\right]_0^3\, dx\\\\V= \frac{4\pi}{9}\cdot 9\\\\V=4\pi](https://tex.z-dn.net/?f=V%3D%5Cint_0%5E3%5Cpi%20%5Ccdot%20%5Cleft%28%5Cfrac%7B2%7D%7B3%7Dx%5Cright%29%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%5Cint_0%5E3%20%5Cpi%20%5Cfrac%7B4%7D%7B9%7Dx%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%20%5Cint_0%5E3%20x%5E2%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%20%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cright%5D_0%5E3%5C%2C%20dx%5C%5C%5C%5CV%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%5Ccdot%209%5C%5C%5C%5CV%3D4%5Cpi)
Therefore, the volume of the cone is V=4π.
Answer:
50/100 x X = 1.5
x 100 x100
50x = 150
÷50 ÷50
X = 3
X = 3 liters I am pretty sure
Answer:
12 pints
Step-by-step explanation:
There are 24 students & each one gets 1 cup, so you will need 24 cups total. There are 2 cups in a pint. You divided the 24 cups you need by 2 cups in a pint to get the answer of 12 pints.
You can double check: 12 pints converted to cups (2 cups in a pint) is 12 x2 = 24 cups
Answer:
1. y= 3x+7
2.y=1/2 x -1
Step-by-step explanation:
1.
Parallel lines have the same gradient.In the equation given,
y= 3x+5 , the slope is 3
So now, you find the equation of a line passing through point (-1,4) with m=3
m=Δ y/Δx
3= y-4/ x--1
3= y-4 /x+1
3(x+1) = y-4
3x+3 =y-4
3x+3+4=y
⇒⇒ y= 3x+7 is the equation.
2.
Two lines that are perpendicular to each other have the product of their slopes to be -1
Given equation to be y= -2x +8 then, m₁ = -2
Finding m₂ will be;
m₁ *m₂ = -1
-2 * m₂ = -1
-2 m₂ = -1
m₂ = -1/-2 = 1/2
So writing the equation of the perpendicular line with m₂ =1/2 , point (-4,-3)
will be;
m=Δy/Δx
1/2=y--3/x--4
1/2 = y+3/x+4
x+4 = 2( y+3)
x+4 = 2(y+3)
x+4 =2y+6
x+4-6=2y
x-2=2y
x/2 -2/2=y
y=1/2 x -1 is the equation.
Cylinders are lengthy and tall and beakers are short and fat
