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DerKrebs [107]
3 years ago
9

At the movie theatre, child admission is $6.30 and adult admission is $9.90 . On Monday, 159 tickets were sold for a total sales

of $1246.50 . How many adult tickets were sold that day? Numberofadulttickets:
Mathematics
1 answer:
frez [133]3 years ago
8 0
C = child tickets
a = adult tickets

Solve this with the substitution method.
Make two equations:

6.30c + 9.90a = 1,246.50
c + a = 159

Solve for c.
Subtract 9.90a from both sides.

6.30c = 1,246.50 - 9.90a
Divide both sides by 6.30.

c = 197.86 - <span>1.57a (rounded to hundredths)
Plug c into second equation.

</span>197.86 - 1.57a + a = 159
Combine like terms.

197.86 - 0.57a = 159
Subtract 197.86 from both sides.

-0.57a = -38.86
Divide both sides by -0.57.

a = <span>68.18
round up to ones: 68

</span>\boxed {68~adult~tickets} were sold.<span>
</span>
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A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili
Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

18x = 3*31

x = \frac{31*3}{18}

x = 5.17

So \mu = 5.17

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

P(X \leq 3) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057

P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294

P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760

P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242

Finally

P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0
4 years ago
An office has 150 employees, and 30 of the employees work the night shift. What percentage of the employees work the night shift
Zanzabum
<h2>Answer:</h2>

The percent of employees who work in the night shift are:

                                     20%

<h2>Step-by-step explanation:</h2>

Total number of employee in the office are: 150

Number of employee who work in the night shift are:  30

The percent of the employee who work in the night shift is calculated as follows:

\dfrac{\text{Number\ of\ people\ working\ in\ the\ night\ shift}}{\text{Total\ number\ of\ employees}}\times 100

Hence, on putting the value in the above formula we get:

=\dfrac{30}{150}\times 100\\\\\\=\dfrac{1}{5}\times 100\\\\\\=20\%

            Hence, the answer is:

                          20%

4 0
3 years ago
Read 2 more answers
(-6time + 3) + (5time -4)
svet-max [94.6K]

Answer:

- 38

Step-by-step explanation:

Here in this question, we have to simplify a certain numeric term to get a simple answer.

The expression is ( - 6 times + 3 ) + ( 5 times - 4 )

= - ( 6 times 3 ) + (5 times - 4)

= - ( 6 × 3 ) - ( 5 × 4 )

= - 18 - 20

= - 38 (Answer)

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Answer:

The answer is -2

Step-by-step explanation:

-6 + 4 = -2

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