Answer:
Step-by-step explanation:
6x+2=9x-1 x=1
6(1)+2=9(1)-1
6+2=9-1
8=8
Hope this helps :)
The domain is all of the possible x values, and there are none less than -3 in this case, so the answer is B, which shows that x must be greater than or equal to -3.
Answer:$4669
Step-by-step explanation:
175x19=3325+5(4)=3345
1300+6(4)=1324
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
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






Note that if a + bi is a root of P(x) = 0, then a – bi is also a root of P(x) = 0.
In this case, i and 7 + 8i are two roots of P(x) = 0. So –i and 7 – 8i are two additional roots of P(x) = 0.