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dalvyx [7]
3 years ago
8

What is the simplified form of cos​ C ? A. √2/2 B. 1 C. √2 D. √5/2

Mathematics
2 answers:
Kruka [31]3 years ago
8 0
The answer is D !!!!!
Igoryamba3 years ago
4 0
The answer is C, √(2).

cosC = 5/(5√2)

5/5 is equal to 1, so they cancel each other out to leave just √2.
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( 5.55 / .15 ) + 7 x .15 = s
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3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
Helga [31]

Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

4 0
3 years ago
Can you please help me out with a question
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The standard equation of a circle is expressed as

(x - h)^2 + (y - k)^2 = r^2

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k is the y coordinate of the center of the circle

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From the graph,

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r = 5

By substituting these values into the equation, we have

(x - - 1)^2 + (y - 4)^2 = 5^2

(x + 1)^2 + (y - 4)^2 = 25

Thus, the equation of the circle is

(x + 1)^2 + (y - 4)^2 = 25

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