Answer:

Step-by-step explanation:
Rn(x) →0
f(x) = 10/x
a = -2
Taylor series for the function <em>f </em>at the number a is:

............ equation (1)
Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2
f(x) = 10/x f(-2) = 10/-2
f'(x) = -10/x² f'(-2) = -10/(-2)²
f"(x) = -10.2/x³ f"(-2) = -10.2/(-2)³
f"'(x) = -10.2.3/x⁴ f'"(-2) = -10.2.3/(-2)⁴
f""(x) = -10.2.3.4/x⁵ f""(-2) = -10.2.3.4/(-2)⁵
∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)
So, we get
Or 
The standard equation of a circle is expressed as
(x - h)^2 + (y - k)^2 = r^2
where
h is the x coordinate of the center of the circle
k is the y coordinate of the center of the circle
r is the radius of the circle(the distance from the center of the circle to the circumference
From the graph,
h = - 1
y = 4
r = 5
By substituting these values into the equation, we have
(x - - 1)^2 + (y - 4)^2 = 5^2
(x + 1)^2 + (y - 4)^2 = 25
Thus, the equation of the circle is
(x + 1)^2 + (y - 4)^2 = 25
how many pounds does he feed his dogs for each meal?