Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35
From the data, we can say the following:
Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43
Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37
Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.
Answer: D
Answer:
27.5 (is greater than) -2.5
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Step-by-step explanation:
Distribute 5/3 to 6x and 9, (5/3•6x)+(5/3•9)=10x+15.
Set 10x+15 equal to 2x-5
10x+15=2x-5
(get rid of the smaller slope)
-2x -2x
8x+15=-5
+15 +15
8x=10
(divide by 8 to get the value of x)
8x divided by 8=x
10 divided by 8=1.25
x=1.25
Plug the known value of x back into the equations.
10(1.25)+15=27.5
2(1.25)-5=-2.5
27.5 (less than or equal to) -2.5 is incorrect. It would be
27.5 (is greater than) -2.5
Answer:
2.5
Step-by-step explanation:
Conversion a mixed number 2 1/
2
to a improper fraction: 2 1/2 = 2 1/
2
= 2 · 2 + 1/
2
= 4 + 1/
2
= 5/
2
To find new numerator:
a) Multiply the whole number 2 by the denominator 2. Whole number 2 equally 2 * 2/
2
= 4/
2
b) Add the answer from previous step 4 to the numerator 1. New numerator is 4 + 1 = 5
c) Write a previous answer (new numerator 5) over the denominator 2.
Two and one half is five halfs
Answer:
(9-27)+9
=-18+9
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