The smallest prime number of p for which p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.
<h3>What is the smallest prime number of p for which p must have exactly 30 positive divisors?</h3>
The smallest number of p in the polynomial equation p^3 + 4p^2 + 4p for which p must have exactly 30 divisors can be determined by factoring the polynomial expression, then equating it to the value of 30.
i.e.
By factorization, we have:
Now, to get exactly 30 divisor.
- (p+2)² requires to give us 15 factors.
Therefore, we can have an equation p + 2 = p₁ × p₂²
where:
- p₁ and p₂ relate to different values of odd prime numbers.
So, for the least values of p + 2, Let us assume that:
p + 2 = 5 × 3²
p + 2 = 5 × 9
p + 2 = 45
p = 45 - 2
p = 43
Therefore, we can conclude that the smallest prime number p such that
p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.
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Answer:
106.6 %.
Step-by-step explanation:
That would be (1060- 513) / 513) * 100
= 106.6 %.
Answer: Never true.
Step-by-step explanation: Distribute the numbers: 4 times x is 4x, 4 times 3 is 12. Then you have the equation: -x+4x +12 = -12. Now, choose a random number, maybe -4. A negative plus a negative cancels out so you are left with 4-16(Because you distribute the number) +12 = -12. 4-16 is -12. -12 plus 12 equals 0.
A. -13
B. -45
C. 20
D. 84
E. 4
F. -4
G. -7
H. 48
The answer will be B because all three angles of the triangles add up to180 degrees, and we already know the total of two other angles are 100 degrees, which made the unknown angles have 80 degrees. Hope it help!
