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3 years ago

I need help ASAP please!!!

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

Answer: The answer is b 100+(-500)

Step-by-step explanation: If you solve for the original and this answer, they will both equal -400

bazaltina [42]3 years ago

4 0

Answer

The answer is B.

Step-by-step explanation:

step 1: 100+(-500)=-400

Step 2: 100-500= -400

also because

A=600

C= 600

D= -600

So...

B is the logical choice

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777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

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Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

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we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

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substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

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<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

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Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

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