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statuscvo [17]
4 years ago
13

Given: AD = BC and BCD = ADC Prove: DE = CE

Mathematics
2 answers:
Romashka-Z-Leto [24]4 years ago
7 0

Answer:

1. AD ≅ BC    [Given]

2. ∠ADC ≅ ∠BCD    [Given]

3. DC ≅ DC    [reflexive property]

4. ΔADC ≅ ΔBCD    [SAS]

5. ∠DAE ≅ ∠CBE    [CPCTC]

6. ∠DEA ≅ ∠CEB    [def. of vertical angles]  

7. ∠DEA ≅ ∠CEB    [vertical angles theorem]

8. ΔAED ≅ ΔBEC    [AAS]

9. DE ≅ CE    [CPCTC]

Step-by-step explanation:

Just finished mine :D

erastova [34]4 years ago
3 0

Answer:

According to AD=BC So AC=BD

Step-by-step explanation:

AD = BC and angle ADC = angle BCD

we have to prove AC = BD

let's see ∆ADC and ∆BCD

AD = BC [ given ]

angle ADC = angle BCD [ given ]

CD = CD

from S - A - S

∆ADC congruence ∆BCD

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Answer:

This makes exactly 0% percent.

Guess:

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4 0
4 years ago
Los profesores de un colegio tienen planeado mandar 6 boletines informativos al año a cada una de las 620 familias con estudiant
alekssr [168]

Answer:

14.88 resmas

Step-by-step explanation:

Los maestros de una escuela planean enviar 6 boletines al año a cada una de las 620 familias con estudiantes en la escuela.

Esto significa: El número total de boletines que recibe cada familia = 6 × 620 familias

= La escuela envía 3720 boletines cada año

Cada uno de los boletines necesita 2 hojas de papel.

1 boletín = 2 hojas de papel

3720 boletines =

Cruz multiplicar

3720 boletines × 2 hojas

= Se necesitan 7440 hojas de papel en un año

El papel se vende en resmas de 500 hojas.

¿Cuál es la cantidad mínima de resmas de papel necesarias para imprimir los boletines escolares en un año?

500 hojas de papel = 1 resma

7440 hojas de papel = y

Cruz multiplicar

500 × y = 7440 × 1

y = 7440/500

y = 14.88 resmas

La cantidad mínima de resmas de papel necesarias para imprimir los boletines escolares en un año es 1488 resmas

8 0
3 years ago
2/5 of the students in your class are in band. Of these, 1/4 play the saxophone. What fraction of your class plays the saxophone
Nimfa-mama [501]
So the problem asks us to find the fraction of your class that plays the saxophone. To find this, all you need to do is divide 2/5 by 1/4. We need to do this because we are basically taking 1/4 of 2/5. When we do this operation, we get 8/5, which is 1 3/5 in mixed fraction form. Hence, the solution to your question is 8/5 or 1 3/5 of the fraction of students in the band play the saxophone. Hope this helps!
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Answer:

Step-by-step explanation:

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