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statuscvo [17]
3 years ago
13

Given: AD = BC and BCD = ADC Prove: DE = CE

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

1. AD ≅ BC    [Given]

2. ∠ADC ≅ ∠BCD    [Given]

3. DC ≅ DC    [reflexive property]

4. ΔADC ≅ ΔBCD    [SAS]

5. ∠DAE ≅ ∠CBE    [CPCTC]

6. ∠DEA ≅ ∠CEB    [def. of vertical angles]  

7. ∠DEA ≅ ∠CEB    [vertical angles theorem]

8. ΔAED ≅ ΔBEC    [AAS]

9. DE ≅ CE    [CPCTC]

Step-by-step explanation:

Just finished mine :D

erastova [34]3 years ago
3 0

Answer:

According to AD=BC So AC=BD

Step-by-step explanation:

AD = BC and angle ADC = angle BCD

we have to prove AC = BD

let's see ∆ADC and ∆BCD

AD = BC [ given ]

angle ADC = angle BCD [ given ]

CD = CD

from S - A - S

∆ADC congruence ∆BCD

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Licemer1 [7]

Given

Let U = {t,u,v,w.x,y,z). A = {w.y}, B = {v,w}, C = {t.x.v}, and D = {v.z.x.t,w}. Tell whether the statement below is true or false. U is the universal set.

Solution

A universal set (usually denoted by U) is a set which has elements of all the related sets, without any repetition of elements.Say if A and B are two sets, such as A = {1,2,3} and B = {1,a,b,c}, then the universal set associated with these two sets is given by U = {1,2,3,a,b,c}.

Since, set A, Set B, Set C and Set D are subset of Set U

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Step-by-step explanation:

11-2(x-5)

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