Given: AD = BC and BCD = ADC
Prove: DE = CE
2 answers:
Answer:
1. AD ≅ BC [Given]
2. ∠ADC ≅ ∠BCD [Given]
3. DC ≅ DC [reflexive property]
4. ΔADC ≅ ΔBCD [SAS]
5. ∠DAE ≅ ∠CBE [CPCTC]
6. ∠DEA ≅ ∠CEB [def. of vertical angles]
7. ∠DEA ≅ ∠CEB [vertical angles theorem]
8. ΔAED ≅ ΔBEC [AAS]
9. DE ≅ CE [CPCTC]
Step-by-step explanation:
Just finished mine :D
Answer:
According to AD=BC So AC=BD
Step-by-step explanation:
AD = BC and angle ADC = angle BCD
we have to prove AC = BD
let's see ∆ADC and ∆BCD
AD = BC [ given ]
angle ADC = angle BCD [ given ]
CD = CD
from S - A - S
∆ADC congruence ∆BCD
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