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3 years ago

Given: AD = BC and BCD = ADC Prove: DE = CE

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

1. AD ≅ BC [Given]

2. ∠ADC ≅ ∠BCD [Given]

3. DC ≅ DC [reflexive property]

4. ΔADC ≅ ΔBCD [SAS]

5. ∠DAE ≅ ∠CBE [CPCTC]

6. ∠DEA ≅ ∠CEB [def. of vertical angles]

7. ∠DEA ≅ ∠CEB [vertical angles theorem]

8. ΔAED ≅ ΔBEC [AAS]

9. DE ≅ CE [CPCTC]

Step-by-step explanation:

Just finished mine :D

erastova [34]3 years ago

3 0

Answer:

According to AD=BC So AC=BD

Step-by-step explanation:

AD = BC and angle ADC = angle BCD

we have to prove AC = BD

let's see ∆ADC and ∆BCD

AD = BC [ given ]

angle ADC = angle BCD [ given ]

CD = CD

from S - A - S

∆ADC congruence ∆BCD

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Step-by-step explanation:

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