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artcher [175]
3 years ago
13

A horse can run 44 per second for several minutes. A cheetah can run faster (88 feet per second) but can only sustain its top sp

eed for about 20 seconds before it is worn out. How far away from the cheetah does the horse need to stay for it to be safe?
Mathematics
1 answer:
qaws [65]3 years ago
6 0

Answer:

44 feet

If it takes the horse 44 feet per second, and it takes the cheetah 88 feet, the difference is 44.

So, the horse must be 44 feet ahead to be safe. Hope it helps!

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Step-by-step explanation:

the hypotenuse should be 3√2*√2=6

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How can you find the whole when you know part and the percent.
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An example should make this clear.

If  $50  is 40%   what is the value of the whole amount?

Answer:-  Whole amount = 100^%

By proportion this =  (100/ 40) * 50

= 2.5 * 50

= $125    (answer)


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A marathon is a race that is 46,145 yards long round this number to the nearest hundred
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Answer:

46,100

Step-by-step explanation:

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Which expression gives the value of x?
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Answer:

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3 years ago
Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0
3 years ago
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