Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
To find the area of this figure, there is two choices
1. cut it into 3 rectangles.
2.find the missing rectangle in the middle......
I likes 2 better $_$ :}
find the missing area in the middle, 12* 23 = 276
the area of the whole figure 31*69-276=1863m²
A graph with y = 2x + 1 is an example of one
ANSWER
Vertex form;
Vertex
EXPLANATION
Given:
We complete the square as follows:
The vertex form is:
The vertex is
Answer:wheres the diagram?
Step-by-step explanation:
