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777dan777 [17]
3 years ago
10

If A = ½ bh, what is the value of A if b = 5 and h = 8? Please help!!!!

Mathematics
2 answers:
tigry1 [53]3 years ago
8 0

Answer: 20

Work: A = 1/2 bh

A = 1/2 (5(8))

A = 1/2 (40)

a = 20

plz mark brainliest

Svetlanka [38]3 years ago
5 0

Answer:

<h2>A = 20</h2>

Step-by-step explanation:

A =  \frac{1}{2} bh

when

b = 5

h = 8

Substitute the values of b and h into the above formula

That's

A =  \frac{1}{2} (8)(5) \\ A  =  \frac{1}{2}  \times 40

We have the final answer as

<h3>A = 20</h3>

Hope this helps you

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation
Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

  • Sample size: n = 20
  • Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}    

This gives

P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}

P(x = 11) = 0.0011

Express as percentage

P(x = 11) = 0.11\%

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all  20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}    

This gives

P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0

P(x = 20) = 0.0388

Express as percentage

P(x = 20) = 3.88\%

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

\mu = np

So, we have:

\mu = 20 \times 85\%

\mu = 17

The standard deviation is calculated as:

\sigma = np(1 - p)

So, we have:

\sigma = 20 \times 85\% \times (1 - 85\%)

\sigma = 20 \times 0.85 \times 0.15

\sigma = 2.55

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0
3 years ago
Tickets for the basketball game were sold at $4.00 for adults and $2.50 for students. If 320 tickets were sold for a total of $1
makkiz [27]

The problem based on condition are solved using the unknown variables. The number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.

Given information-

The price of the tickets for the basketball game for adults is $4.00.

The price of the tickets for the basketball game for students is $2.50.

<h3>Variables</h3>

Variables are the unknown and the value of the variables depend on the other variables in the equation. The above problem can be solved defining the variables from the given condition.

Let the total tickets purchased by the students is<em> x</em> and the total tickets porches by the adults is <em>y.</em>

As the total tickets sold for the game is $320. Thus,

\begin{aligned}\\&#10;x+y&=320\\&#10;y&=320-x\\&#10;\end                    .......1

Now as the total money with ticket selling is $1100. Thus,

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\begin{aligned}&#10;2.5x+4(320-x)&=1100\\&#10;2.5x+1280-4x&=1100\\&#10;-1.5x&=1100-1280\\&#10;-1.5x&=-180\\&#10;x&=\dfrac{180}{1.5} \\&#10;x&=120\\&#10;\end

Thus the number of tickets sold to the student are 120.

Keep this value in equation 1,

y=320-x\\&#10;y=320-120\\&#10;y=200

Thus the number of tickets sold to the adults are 200.

Hence the number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.

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