General equation of parabola
for vertex(h,k)
Now





So
equation of parabola

Answer:
16
Step-by-step explanation:
The existence of the constant rate of change is given the ratio of y to x is the same. Then:






In consequence, the constant rate of change is 16.
Answer:
Yes
Step-by-step explanation:
If you multiple 1/3 by 3/3 you would get 3/18
C=2•pi• R
D=6 then the radius is 3
2•Pi•3 =18.85