To solve this problem, we use the formula:
z = (x – u) / s
where z is the z score value which can be obtained from
the tables, x is the sample value, u is the mean = 6.3 min, and s is the std
dev = 2.2 min
at P value = 0.90, the z = 1.28, finding for x:
x = z s + u
x = 1.28 * 2.2 + 6.3
x = 9.116
at P value = 1.0, the z = 3.49, finding for x:
x = z s + u
x = 3.49 * 2.2 + 6.3
x = 13.978 ~ 14
Therefore the longest 10% calls last about 9.1 minutes to
14 minutes
Answer:
9, -3
Step-by-step explanation:
Answer:
Answer is C
Step-by-step explanation:
hope you have s good day
You would do $5.67 divided by three. one pen is $1.89
The value of ![f(x+2)=2.1x+2.5](https://tex.z-dn.net/?f=f%28x%2B2%29%3D2.1x%2B2.5)
Step-by-step explanation:
Given: The function ![f(x)=2.1x-1.7](https://tex.z-dn.net/?f=f%28x%29%3D2.1x-1.7)
Using this formula, we need to find the value of ![f(x+2)](https://tex.z-dn.net/?f=f%28x%2B2%29)
Hence, we need to substitute
by
to find the value of ![f(x+2)](https://tex.z-dn.net/?f=f%28x%2B2%29)
![f(x+2)=2.1(x+2)-1.7](https://tex.z-dn.net/?f=f%28x%2B2%29%3D2.1%28x%2B2%29-1.7)
Multiplying the term
by
, we get,
![f(x+2)=2.1x+4.2-1.7](https://tex.z-dn.net/?f=f%28x%2B2%29%3D2.1x%2B4.2-1.7)
Adding the constant term,
![f(x+2)=2.1x+2.5](https://tex.z-dn.net/?f=f%28x%2B2%29%3D2.1x%2B2.5)
Thus, the value of
is ![f(x+2)=2.1x+2.5](https://tex.z-dn.net/?f=f%28x%2B2%29%3D2.1x%2B2.5)