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makkiz [27]
3 years ago
14

How many ways are there for a child to take 10 pieces of candy with four types of candy if the child does not take exactly two p

ieces of any type of candy?
Mathematics
1 answer:
leonid [27]3 years ago
6 0
MAny ways the child can thake 5 of the 2 ones she likes or 8 of one and 2 of the other or 4 of one and 6 of the other 7 of one 3 of the onther 9 of 1 and and 1 of the other. you can find the rest
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Use the properities to find the sum or product of 93+[68+7]
kondor19780726 [428]

Answer:

the answer for this questionis 93(68+7)

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Please look at a the attached image below, it’s urgent
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40⁰ is angle boc

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2 years ago
Two machines are used for filling plastic bottles to a net volume of 16.0 ounces. A member of the quality engineering staff susp
aleksandrvk [35]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the two machines are filling the bottles with a net volume of 16.0 ounces or if at least one of them is different.

The parameter of interest is μ₁ - μ₂, if both machines are filling the same net volume this difference will be zero, if not it will be different.

You have one sample of ten bottles filled by each machine and the net volume of the bottles are measured, determining two variables of interest:

Sample 1 - Machine 1

X₁: Net volume of a plastic bottle filled by the machine 1.

n₁= 10

X[bar]₁= 16.02

S₁= 0.03

Sample 2 - Machine 2

X₂: Net volume of a plastic bottle filled by the machine 2

n₂= 10

X[bar]₂= 16.01

S₂= 0.03

With p-values 0.4209 (for X₁) and 0.6174 (for X₂) for the normality test and using α: 0.05, we can say that both variables of interest have a normal distribution:

X₁~N(μ₁;δ₁²)

X₂~N(μ₂;δ₂²)

Both population variances are unknown you have to conduct a homogeneity of variances test to see if they are equal (if they are you can conduct a pooled t-test) or different (if the variances are different you have to use the Welche's t-test)

H₀: δ₁²/δ₂²=1

H₁: δ₁²/δ₂²≠1

α: 0.05

F= \frac{S^2_1}{S^2_2} * \frac{Sigma^2_1}{Sigma^2_2} ~~F_{n_1-1;n_2-1}

Using a statistic software I've calculated the test

F_{H_0}= 1.41

p-value 0.6168

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis then you can conclude that both population variances for the net volume filled in the plastic bottles by machines 1 and 2 are equal.

To study the difference between the population means you can use

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~~t_{n_1+n_2-2}

The hypotheses of interest are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

Sa= \sqrt{\frac{(n_1-1)S^2_1+(N_2-1)S^2_2}{n_1+n_2-2}} = \sqrt{\frac{9*9.2*10^{-4}+9*6.5*10^{-4}}{10+10-2} } = 0.028= 0.03

t_{H_0}= \frac{(16.02-16.01)-0}{0.03*\sqrt{\frac{1}{10} +\frac{1}{10} } } = 0.149= 0.15

The p-value for this test is: 0.882433

The p-value is greater than the significance level, the decision is to not reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to reject the null hypothesis. You can conclude that the population average of the net volume of the plastic bottles filled by machine one and by machine 2 are equal.

I hope this helps!

8 0
3 years ago
Quick!!!!!!!!!!!!!!!
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Answer: discrete.

Step-by-step explanation:

Discrete variable

It is a variable whose value is evaluated by counting.

Example: Number of books published in a month.

Continuous variable

It is a variable whose value is evaluated by measuring ( not countable).

Example: Distance: 1.52 m

Since the number of dental visits a randomly chosen person had for the past 5 years is a countable.

here, Variable: Let X =number of dental visits a randomly chosen person had for the past 5 years

So, the random variable described is discrete.

7 0
3 years ago
A museum has a 1/1000 scale model of the Grand Canyon, complete with a miniature river in the bottom. Explain how you could use
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