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Furkat [3]
3 years ago
13

Write an expression equivalent to -8(10x - 3)

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

The expression is -80x+24

Step-by-step explanation:

distribute the -8

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Concider the functions: f(x)= (2/3)x and g(x)=(2/3)x-3+2. Which statement is true regarding the vertical and horizontal translat
ioda

The function g(x) is a translation to the right of 3 units and up 2 units of f(x), so the correct option is B.

<h3>Which statement is true regarding the vertical and horizontal translations from f(x) to g(x)?</h3>

For a given function f(x), we can write a vertical translation of n units as:

g(x) = f(x) + n

  • If n < 0, the translation is downwards.
  • if n > 0, the translation is upwards.

And a horizontal translation of n units as:

g(x) = f(x + n).

  • if n > 0, the translation is to the left.
  • if n < 0, the translation is to the right.

Here we have:

f(x) = (2/3)*x

g(x) = (2/3)*(x - 3) + 2

By comparing it with the general translations, we conclude that we have a traslation of 3 units to the right and 2 units up.

So the correct option is B.

If you want to learn more about translations:

brainly.com/question/24850937

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4 0
2 years ago
Katie and Danielle recorded their resting heart rates each morning for ten days. The double dot plot shows their heart rates in
gladu [14]

Answer:

I think it is G

Step-by-step explanation:

So ya see, it really does peak at the given times.

8 0
3 years ago
the sum of three consecutive integers is three times the second integer. show that this is true for the three consecutive intege
sdas [7]

Step-by-step explanation:

7+8+9=24

second integer is 8 so 8*3=24

3 0
3 years ago
Please help me right away with these problems.
viktelen [127]

Q.34

\sum\limits_{k=1}^{\infty}420\left(1.002\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r =1.002 > 1, therefore our infinite geometric series is Diverges

Answer: c. Diverges, sum not exist.

Q.35

\sum\limits_{k=1}^{\infty}-5\left(\dfrac{4}{5}\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r = 4/5 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

S=\dfrac{a_1}{1-r}

We have:

a_1=-5\left(\dfrac{4}{5}\right)^{1-1}=-5\left(\dfrac{4}{5}\right)^0=-5\\\\r=\dfrac{4}{5}

substitute:

S=\dfrac{-5}{1-\frac{4}{5}}=-\dfrac{5}{\frac{1}{5}}=-5\cdot\dfrac{5}{1}=-25

Answer: c. Converges, -25.

4 0
3 years ago
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Recall that sin(π/2) = 1, and cos(π/2) = 0,

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7 0
3 years ago
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