Starting at the decimal point ...
-- Look at all the digits in the <u>first</u> place after the decimal point.
Find the smallest one. If more than one number has that digit
in the first place, then keep those, discard the others, and ...
-- Look at the digits in the <u>second</u> place after the decimal point.
Find the smallest one. If more than one number has that digit
in the second place, then keep those, discard the others, and ...
-- Look at the digits in the <u>third</u> place after the decimal point.
Find the smallest one. If more than one number has that digit
in the third place, then keep those, discard the others, and ...
-- Look at all the digits in the <u>fourth</u> place after the decimal point.
Find the smallest one. If more than one number has that digit in
the fourth place, then keep those, discard the others and ...
.
.
.
etc.
Keep going until you have only one number left. That's the smallest one,
out of the entire original list.
In the example you gave, the smallest digit in the first place after the decimal point
is the '0', and choice-'C' is the only one that has it. So choice-'C' is the least, and
you don't need to go any farther.
Here's another one to practice on. It needs the whole procedure that I wrote out,
but now it should be easy for you:
0.1234607
0.1234915
0.1234095
0.1234017
0.1234184
0.1234521
Answer:
36
Step-by-step explanation:
the steps are in the attached doc.
Still need 13-5=8 blankets
8/20=4/10=0.4
0.4*100%=40%
Answer:
64 = 4x
64 divided by the total sides the garden has, 4
Given :
You decide to run at least 7.5 miles per week during the week to train for the cross-country season in the fall.
During one week, you run 2 miles on Sunday and 2.5 miles on Wednesday.
To Find :
How many more miles, m, do you need to run before the week is over.
Solution :
Total number of miles we travelled till Wednesday :
t = miles run on Sunday + miles run on Wednesday
t = 2 + 2.5 miles = 4.5 miles.
Now, number of miles remaining :
R = Total target - t
R = 7.5 - 4.5 miles
R = 3 miles.
Therefore, we need to run 3 more miles before the week is over.
Hence, this is the required solution.