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EleoNora [17]
3 years ago
8

Whats the answer____________________

Mathematics
2 answers:
neonofarm [45]3 years ago
7 0
(4x+2)(4x-2)      = 4x*4x = 16
                              2*-2 =  -4


16^2 - 4 

Hope this helped! :)
inessss [21]3 years ago
4 0
 the answer is 16x^2-4
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Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
3 years ago
Find the missing factor. 6x^2+7x-5=(3x+5)( )
Tpy6a [65]
6x^2 + 7x - 5 = (3x + 5)(2x - 1)

Its 2x - 1
8 0
3 years ago
Read 2 more answers
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

du=dx         v=2\cdot{e^(2x)}

\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du

\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx

\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C

We can therefore determine that if x tends to 0 the limit is -1

\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1

5 0
3 years ago
1. x + 2 = 8<br> How to solve this problem
s344n2d4d5 [400]

Answer:

Subtract two from 8, the remainder is x. In this case, it is 6.

For future questions, try to think of x as a mystery number rather than a letter. You got this. :)

3 0
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Please help and give brainliest answer
mixas84 [53]

Answer:

I believe it is Dilation

Step-by-step explanation:

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3 years ago
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