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3 years ago

Please Help!

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

8 0

There is an infinite number of values that are in both the domain and range.

arsen [322]3 years ago

7 0

Answer:

100% sure There is an infinite number of values that are in both the domain and range.

Step-by-step explanation:

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What is an end point of a ray

Alborosie

An angle is the union of two rays with a common endpoint. The common endpoint of the rays is called the vertex of the angle, and the rays themselves are called the sides of the angle.

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2 years ago

Classify the following random variables as discrete or continuous:X: the number of automobile accidents per year in Virginia. Y

Elena-2011 [213]

Answer:

X: discrete

Y: continuous

M: continuous

N: discrete

P: discrete

Q: continuous

Step-by-step explanation:

First, we have to know the difference between discrete and continuous variables:

Discrete variables are those that represent things that are counted, 3 red cars, 2 chickens, etc.. They take positive integer values, {0, 1, 2, ..., n}, being [0, n] the interval from which the variable takes values, that means, there is a finite number of possible values.
Continuous variables are those that represent things that are measured, 3.56 km of railway laid, 5.77 l of paint used. They take positive real values, that means that in the interval used for the variable there are infinite possible values.

Now, we classify each variable:

The number of automobile accidents per year in Virginia (X) is a discrete variable, as there can't be half an accident, one counts how many accidents are per year to know X.
The length of time to play 18 holes of golf (Y) is a continuous variable, as it can take 2 hours, or 2.5 hours, or 2 hours, 30 minutes, 2 seconds, one measures how long it took to play 18 holes to know Y.
The amount of milk produced yearly by a particular cow (M) is a continuous variable, as one measures how much milk was produced to know M.
The number of eggs laid each month by a hen (N) is a discrete variable, as one counts how much eggs were laid to know N.
The number of building permits issued each month in a certain city (P) is a discrete variable, as one counts how many permits were issued to know P.
The weight of grain produced per acre (Q) is a continuous variable, as one measures the weight per acre to know Q.

3 0

3 years ago

Suppose Cone A is similar to Cone B and the scale factor between the solids is 3:2, respectively. If the height of Cone A is 15

blondinia [14]

Answer:

$10\ inches$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

Let

x----> the height of cone B

using proportion

$\frac{3}{2}=\frac{15}{x} \\ \\x=2*15/3\\ \\x=10\ in$

4 0

3 years ago

The perimater of the triangle is 30cm. its sides are in the ratios 1:3:2, then find its sides

DiKsa [7]

Answer:

1 * 5 = 5cm

3 * 5 = 15cm

2 * 5 = 10cm

Step-by-step explanation:

1+3+2 = 6

then do 30 / 6 = 5 to find one part of the ratio

1 * 5 = 5

3 * 5 = 15

2 * 5 = 10

8 0

3 years ago

Read 2 more answers

You have one type of nut that sells for $2.80/lb and another type of nut that sells for $9.60/lb. You would like to have 20.4 lb

max2010maxim [7]

Answer:11.396Ibs of nuts that cost $9.60/Ib and 9.014Ibs that cost $2.80/Ib

Step-by-step explanation:

First we find the cost of the supposed mixture we are to get by selling it $6.60/Ib which weighs 20.41Ibs

Which is 6.6 x 20.41 = $134.64

Now we label the amount of mixture we want to get with x and y

x = amount of nuts that cost $2.8/Ib

y = amount of nuts that cost $9.6/Ib

Now we know the amount of mixture needed is 20.41Ibs

So x + y = 20.41Ibs

And then since the price of the mixture to be gotten overall is $134.64

We develop an equation with x and y for that same amount

We know the first type of nut is $2.8/Ib

So for x amount we have 2.8x

For the second type of nut that is $9.6/Ib

For y amount we have 9.6y

So adding these to equate to $134.64

2.8x + 9.6y = 134.64

So we have two simultaneous equations

x + y = 20.41 (1)

2.8x + 9.6y = 57.148 (2)

We can solve either using elimination or factorization method

I'm using elimination method

Multiplying the first equation by 2.8 so that the coefficient of x for both equations will be the same

2.8x + 2.8y = 57.148

2.8x + 9.6y = 134.64

Subtracting both equations

-6.8y = -77.492

Dividing both sides by -6.8

y = -77.492/-6.8 =11.396

y = 11.396Ibs which is the amount of nuts that cost $9.6/Ib

Putting y = 11.396 in (1)

x + y = 20.41 (1)

x +11.396 = 20.41

Subtract 11.396 from both sides

x +11.396-11.396 = 20.41-11.396

x = 9.014Ibs which is the amount of nuts that cost $2.8/Ibs

8 0

3 years ago