So basically from (-2,6) to (1,6)
The up and down translations applies to the y values
So from 6 to 6 nothing happened! so wasn't translated neither up nor down
And left and right applies to x values.
from -2 to 1
3 units positive that means 3 units right..
Hope it helps
Answer:
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have 
and for the denominator we have 
and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:
For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different
Step-by-step explanation:
Information given
represent the sampe size 1
represent the sample 2
represent the sample deviation for 1
represent the sample variance for 2
represent the significance level provided
The statistic is given by:
Hypothesis to test
We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:
H0: 
H1: 
The statistic is given by:
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have and for the denominator we have and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:
For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different
Answer:
e find Ad. Explain your answer
Answer: 2a - 10
Step-by-step explanation:
a represents the number of students in the art club.
The number of students in a school's math club is ten less than twice the number of students in the art club.
ten less = - 10
twice the number of students in the art club = 2*a
2a - 10 = the number of students in the math club
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
