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Ksenya-84 [330]
3 years ago
10

A cheese pizza costs $5. Additional toppings cost $1.50 each. Write and graph an equation in two variables that represents the t

otal cost of a pizza. Let tt represent the number of toppings and c represent the total cost of the pizza. An equation in two variables that represents the total cost of a pizza is c=____
Mathematics
1 answer:
aivan3 [116]3 years ago
5 0
$6.50 I guess, because I added $5 and $1.50 and got $6.50
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A bookstore marks up the price of a book by 25% of the cost from the publisher. Therefore, the
lesya692 [45]

Answer:

(A)

  • P(60) = 78.98
  • When the bookstore spends $60 on a textbook, the student pays $78.98

Step-by-step explanation:

Given:

P(x) = 1.053(x+0.25x)

P(60) = 1.053(60+0.25*60)

=1.053(60+15)

=1.053(75)

P(60)=$78.98

Since x is the cost from the publisher, when the bookstore spends $60 on a textbook, the student pays $78.98.

<u>The correct option is A.</u>

3 0
3 years ago
Demetrius is single but would like to take care of his mother in the event of his death. He would like to replace her income of
Helen [10]

Answer:

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Step-by-step explanation:

8 0
1 year ago
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
Are 27/4 and 32/3 equivalent fractions?
Blababa [14]

Answer:

no

Step-by-step explanation:

27/4 = 54/8 = 81/12 = 108/16

= 135/20 = 162/24 = 189/28 = 216/32

= 243/36 = 270/40 = 297/44 = 324/48

= 351/52 = 378/56 = 405/60 = 432/64

= 459/68 = 486/72 = 513/76 = 540/80

= 567/84 = 594/88 = 621/92 = 648/96

= 675/100 = 702/104 = 729/108 = 756/112

= 783/116 = 810/120 = 837/124 = 864/128

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= 999/148 = 1026/152 = 1053/156 = 1080/160

= 1107/164 = 1134/168 = 1161/172 = 1188/176

= 1215/180 = 1242/184 = 1269/188 = 1296/192

= 1323/196 = 1350/200 = 1377/204 = 1404/208

= 1431/212 = 1458/216 = 1485/220 = 1512/224

= 1539/228 = 1566/232 = 1593/236 = 1620/240

= 1647/244 = 1674/248 = 1701/252 = 1728/256

= 1755/260 = 1782/264 = 1809/268 = 1836/272

= 1863/276 = 1890/280 = 1917/284 = 1944/288

= 1971/292 = 1998/296 = 2025/300 = 2052/304

= 2079/308 = 2106/312 = 2133/316 = 2160/320

= 2187/324 = 2214/328 = 2241/332 = 2268/336

= 2295/340 = 2322/344 = 2349/348 = 2376/352

= 2403/356 = 2430/360 = 2457/364 = 2484/368

= 2511/372 = 2538/376 = 2565/380 = 2592/384

= 2619/388 = 2646/392 = 2673/396 = 2700/400

8 0
2 years ago
Read 2 more answers
Each lap around the track is 400 meters. How many meters does someone run if they run 5 laps?
Luda [366]

Answer:

2000 meters

Step-by-step explanation:

400×5=2000

4 0
2 years ago
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