Answer:
not sure for the 1st one but pretty sure 2nd one is B
Step-by-step explanation:
The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer:
Width: x + 3
(Length, width):
(5,4) (6,5) (7,6)
Step-by-step explanation:
x² + 7x + 12
x² + 4x + 3x + 12
x(x + 4) + 3(x + 4)
(x + 4)(x + 3)
Longer one is the length,
With is (x + 3)
x = 1,
5 × 4
x = 2,
6 × 5
x = 3,
7 × 6
6; because they are an equal distance apart
Step-by-step explanation:
Step 1: 25*x-((1/125)^(4*x-5))=0
step 2: simplify 1/125
step 3: 25x-(1/125)(4x-5)=0
pls i need one more brainly
