Answer:
Choice B, C, and D.
Explanation:
Choice A is not true in general. Here's a way to think about that. Consider a very special equilibrium where the concentration of reactants and products are indeed equal. When one of the external factors (such as temperature) changes, the equilibrium will shift towards either side of the reaction. More products will be converted to reactants, or vice versa. Either way, in the new equilibrium, the concentration of the reactants and products will not be equal any more.
Choice B should be considered with choice C and D in mind.
Choice C is indeed correct. The reaction rate would not be zero unless all the reactants were used up or taken out of the system. That's not what happens in an equilibrium. Instead, when reaction rate is plotted against time, the graph for reactions in both directions will eventually flat out at a non-zero value.
Choice D explains why even though choice C is correct, the concentration of a system at equilibrium stays the same. At the equilibrium, reactions in both directions are still happening. However, during the time it takes for the forward reaction use up some reactant particles, the reverse reaction would have produced these particles again. On a large scale, there would be no observable change to the concentration of each species in the equilibrium. Therefore, choice B is also correct.
Answer:
Mitochondria
Explanation:
Glucose in an energy molecule contained in carbohydrate food substances. The end product of the digestion of carbohydrate is glucose which is broken down to produce energy.
The sequence of breakdown of glucose is as follows; In the first step, 6-carbon glucose is broken down into two molecules of 3-carbon pyruvic acid. This occurs in the cytoplasm of the cell. It is an anaerobic process.
In the second step which occurs in the mitochondrion, each of the molecules of pyruvic acid is now oxidized to carbon dioxide and water and energy is produced in the process.
Explanation:
A period 4 element is one of the chemical elements in the fourth row (or period) of the periodic table of the elements.
...
Period 4 element.
Hydrogen Rubidium
Strontium
Yttrium
Zirconium
Niobium
Answer:
I think your correct but I'm not so sure