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kogti [31]
3 years ago
13

ASK A QUESTION Weekly wages at a certain factory are normally distributed with s mean of $400 and a standard deviation of $50. F

ind the probability that a worker selected at random makes between $250 and $300.
Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0

Weekly wages are normally distributed with a mean of $400

standard deviation of $50

we are supposed to find the probability that a worker selected at random makes between $250 and $300.

The z-Score can be written as

z=\frac{x-\mu}{\sigma } \\ \\ z=\frac{300-400}{50}=-2\\ \\  z=\frac{250-400}{50}=-3\\

Now as we can write the probability as

P(-3\leq z\leq -2)=P( z\leq -2)-P( z\leq -3)\\ \\

Now using the Z-score table we can write

P(-3\leq z\leq -2)=0.0227-0.0014\\ \\ P(-3\leq z\leq -2)=0.0213

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Which represents the solution(s) of the system of equations, y = x2 – 6x + 8 and y = –x + 4? Determine the solution set by graph
Sergio039 [100]

Answer:

C) (1,3) and ( 4,0)

The intersecting points of two given curves are A( 1,3) and B(4,0)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given Parabola  y = x² – 6x + 8  and straight line y = -x +4

      y = x² – 6x + 8   ...(i)

      y = -x +4  ...(ii)

Equating (i) and (ii) equations , we get

  x² – 6x + 8  = -x +4

⇒ x² – 6x + 8  +x - 4 = 0

⇒ x² – 5x +  4 = 0

⇒ x² – 4x -x + 4 = 0

⇒ x ( x-4) -1( x -4) =0

⇒ (x -1) ( x -4) =0

⇒ x =1 and x = 4

<u><em>Step(ii):-</em></u>

Put x = 1 in equation y = -x +4

  y = -1 +4 = 3

The first point A( 1,3)

Put x = 4 in equation y = -x +4

y = -4+4 =0

The second point B(4,0)

<u><em>Final answer:</em></u>-

The intersecting points of two given curves are A( 1,3) and B(4,0)

8 0
3 years ago
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A local theatre sells out for their show. They sell all 500 tickets for a total purse of $7,920.00. The tickets were priced at $
Arte-miy333 [17]

Answer:

number of children ticket sold = 70

number of adult ticket sold = 70 × 3 = 210

number of student ticket sold = 500 - 4(70) = 500 - 280 = 220

Step-by-step explanation:

A local theater sells out their show. They sell all 500 tickets for a total of $7920 .00 .  The total number of ticket sold is 500.

let

Number of children ticket sold = a

Adult ticket sold = 3a

Student ticket sold = 500 - 3a - a = 500 - 4a

Total cost = 7920

7920 = 12(a) + 15(500 - 4a) + 18(3a)

7920 = 12a + 7500 - 60a + 54a

collect like terms

7920 = 12a - 60a + 54a + 7500

7920 - 7500 = 6a

420 = 6a

divide both sides by 6

a = 420/6

a = 70

number of children ticket sold = 70

number of adult ticket sold = 70 × 3 = 210

number of student ticket sold = 500 - 4(70) = 500 - 280 = 220

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