The answer for this problem is 1893 Cm squared.
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
Answer:
L = the length of the field
W = the width of the field
The First Question:
The system is: L - 12 = w
2L + 2W = 76
Plug in L - 12 for W and you will get
2L + 2L - 24 = 76
4L -24 = 76
4L = 100
L = 25
To find W do L - 12 = w
25 - 12 = w
w = 13
Answer:
6/12, 8/12, and 9/12.
Step-by-step explanation:
Let's find the least common denominator:
First, the least common multiple of 2, 3, and 4 is 12.
12 is divisible by 2, 3, and 4.
<u>Next, multiply the denominators with the numerators:</u>
Products: 6/12, 8/12, and 9/12
