Question

I NEED HELP ON THESE PLSS

Answer 1

Question 1

$2(5y-2)=12+6y$

Distributing 2 on 5y -2, we will get

$10y-4=12+6y$

But student get

$7y-4=12+6y$

So the student make an error in step 2 .

Second question

$Equation \ P : y+z=6 \\ Equation \ Q : 8y+7z=1$

To get rid of y, we have to multiply first equation by -8 and add the resultant equation with equation Q .