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3 years ago

I NEED HELP ON THESE PLSS

Mathematics

1 answer:

mafiozo [28]3 years ago

4 0

Question 1

$2(5y-2)=12+6y$

Distributing 2 on 5y -2, we will get

$10y-4=12+6y$

But student get

$7y-4=12+6y$

So the student make an error in step 2 .

Second question

$Equation \ P : y+z=6 \\ Equation \ Q : 8y+7z=1$

To get rid of y, we have to multiply first equation by -8 and add the resultant equation with equation Q .

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Find the area of a circle with a diameter of 4

rusak2 [61]

Answer:

12. 56

Step-by-step explanation:

The area of a circle is given by pi×r^2

where r is the radius. The question states That we should use 3. 14 in place of pi.

Area=3. 14×r^2

=3. 14×2^2

=3. 13×4

=12. 56

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3 years ago

Gordon types 2,508 words in 38 minutes. Find the unit rate. Gordon types words per minute.

iris [78.8K]

Answer:

66 words per minute

Step-by-step explanation:

In 38 minutes , words that can be typed by Gordon = 2508 words

In 1 minute, words that can be typed by Gordon = 2508/38

= 66 words

Therefore Gordon types 66 words per minute.

hope it helps :)

3 0

3 years ago

Read 2 more answers

Find the heart rates of you and your friend. do these rates form a proportion? explain.

MArishka [77]

Answer:

what is the question? I do not get what the question is.

8 0

3 years ago

A distribution consists of three components with frequencies 45 ,40 and 15 having their means 2,2.5 and 2 respectively . find co

mash [69]

Solution: A distribution consists of three components with frequencies 45 ,40 and 15 having their means 2,2.5 and 2 respectively . find combined mean

Answer: Let $\bar{x_{1}}$ be the mean of first component and $n_{1}$ be the frequency of first component

Let $\bar{x_{2}}$ be the mean of second component and $n_{2}$ be the frequency of second component

Let $\bar{x_{3}}$ be the mean of third component and $n_{3}$ be the frequency of third component

Then we have:

$\bar{x_{1}} = 2, n_{1} = 45$

$\bar{x_{2}} = 2.5, n_{2} = 40$

$\bar{x_{3}} = 2, n_{3} = 15$

Now the combined mean is:

Combined mean $=\frac{\bar{x_{1}} \times n_{1}+\bar{x_{2}} \times n_{2}+\bar{x_{3}} \times n_{3}}{n_{1} +n_{2} +n_{3}}$

$=\frac{2 \times 45 +2.5 \times 40 +2 \times 15}{45+40+15}$

$=\frac{90 + 100 + 30}{100}$

$=\frac{220}{100}=2.2$

Therefore, the combined mean is 2.2

6 0

4 years ago

ALGEBRAIC model that represents the following situation: "A local fair charges an entrance fee of $5, and costs $1.25 per ride.

Sergeu [11.5K]

Answer:

y = 1.25x + 5

Step-by-step explanation:

The entrance fee is fixed, meaning it does not change. It is $5 for any person that wants to enter.

y = mx + b

only rates that change is dependent on how many rides you go on.

so 1.25 is your slope, m

y = the amount you will spend

x = the amount of rides you go on

b = the cost to enter the fair -- this is fixed.

put the equation together

6 0

3 years ago