Question

Solve the system of linear equations below. X+y=4 2x+3y=0

Answer 1

X + y = 4...x = 4 - y

2x + 3y = 0
2(4-y) + 3y = 0
8 - 2y + 3y = 0
-2y + 3y = 0 - 8
y = -8

x + y = 4
x - 8 = 4
x = 4 + 8
x = 12

solution is : (12,-8)

Answer 2

Answer: x=12 and y=-8

Step-by-step explanation:

The given system of linear equations: $x+y=4..............(1)\\2x+3y=0...............(2)$

Multiply 2 on both sides in equation (1), we get

$2x+2y=8.......................(3)$

Using elimination method, eliminate equation (3) from (2), we get

$y=-8$

When we substitute the value of y in equation (1), we get

$x-8=4\\\\\Rightarrow\ x=8+4=12$

Hence, the solution of the given system is x=12 and y=-8.