1.) Jarvis lives 3 miles away from Cassidy and Theo lives 6 miles away.
(if Jarvis lives 3 miles away from Cassidy and Theo is twice as far from Jarvis, Theo would be twice as many miles away from Cassidy than Jarvis; 3 times 2 is 6; 3+6+=9)
2.) Jorge's watering can can hold 8 cups of water.
(Older brother's can hold 16 cups; 8+8+16= 32; there are 32 cups in 2 gallons)
Answer:
28%
Step-by-step explanation:
Part A: 42.50+0.65x<60
Part B: You can enjoy maximum 26 rides at the fairy tale spectacular.
Step-by-step explanation:
Given,
Admission cost to fair = $42.50
Cost of each ride = $0.65
Amount you can spend = $60
Let,
x be the number of rides you can take.
Admission fair + Cost of each ride*number of rides < Amount you can spend
Part A: write an inequality that represents this situation.
42.50+0.65x<60
Part B: solve the inequality to determine the maximum number of rides you can enjoy at the fairy tale spectacular.

Dividing both sides by 0.65

Rounding off to nearest whole number;
x<27
Less than 27 means, you cannot take 27 rides, therefore,
You can enjoy maximum 26 rides at the fairy tale spectacular.
Keywords: inequality, division
Learn more about inequalities at:
#LearnwithBrainly
Answer:
111011
Step-by-step explanation:
Following the binary rule we can find the base 2 presentation of the decimal number 59.
To find the binary equivalence of 59 we use the sum of powers of 2.







Now we take our number and find out what the binary number will by taking our largest number closest to the number first.
59 = 32
We chose the number 32 since 64 will be a larger value than 59.
We then check how much we have to add to 32 to get 59.
59 = 32 + 27
We then look for the closest number to 27 in our powers of 2.
59 = 32 + 16
Now we check again for how much we need left to get a total of 59.
59 = 32 + 16 + 11
Now we repeat the same process of finding which value in the powers of 2 are closest to the number.
59 = 32 + 16 + 8 + 3
59 = 32 + 16 + 8 + 2 + 1
Now since we already have a total of 59, our binary number will be all the numbers present will have a value of 1 and the numbers now used will have a number of 0.
32 16 8 4 2 1
This can also be represented as:
2^5 2^4 2^3 2^1 2^0
Now we have to include the numbers that we skipped to get the total binary number.
32 16 8 4 2 1
1 1 1 0 1 1
This can be represented as:
59 = 32 16 + 8 + 0 + 2 + 1
1 1 1 0 1 1
Answer:
(-3,-5)
Step-by-step explanation:
2x=-6
x=-3
24+3y=9
3y=-15
y=-5