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cricket20 [7]
3 years ago
14

Hi I know its a lot of rate of change I just don't understand

Mathematics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

m=4

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Slope Formula (Rate of Change): m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (0, 0)

Point (1, 4)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                     m=\frac{4-0}{1-0}
  2. Subtract:                        m=\frac{4}{1}
  3. Divide:                           m=4
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The mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of
masya89 [10]

Answer:

Z=±1.65

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

System of hypothesis

Null hypothesis: \mu=20000

Alternative hypothesis: \mu \neq 20000

If the random variable is distributed like this: X \sim N(\mu=20000,\sigma=2000)

The significance level provided is \alpha=0.1 and the value of \alpha/2= 0.05.

Since we are conducting a bilateral test, then we have two critical values. We need to find two quantiles that accumulates 0.05 of the area on the tails of the normal standard distribution. And in order to find it we can use the following excel codes:

"=NORM.INV(0.05,0,1)" , "=NORM.INV(1-0.05,0,1)"

And we got this:

z_{\alpha/2}=-1.65 and z_{1-\alpha/2}=1.65

So the correct answer for this case is:

Z=±1.65

8 0
3 years ago
I need help someone help
Alex17521 [72]

D is the answer

because you are doing y=2(x+3)^2 - 5

First, do exponents

(x+3)(x+3) = x^2 + 6x + 9

now Multiply your answer by 2

2(x^2 +6x + 9) = 2x^2 + 12x + 18

Then, Subtract 5 from 18

2x^2 +12x + 18-5 = 2x^2 + 12x + 13

bringing you to answer D


3 0
2 years ago
Read 2 more answers
Which point is located at -8.65−8.65minus, 8, point, 65?
ikadub [295]

The question is an illustration of a number line, and the point located at -8.65 is B

<h3>How to determine the point?</h3>

From the complete question, we have the following highlight

Point B is between -8 and -9, and point B is closer to -9 than -8

No other point is between -8 and -9

So, we can conclude that the point located at -8.65 is point B

Read more about number lines at:

brainly.com/question/4727909

#SPJ1

4 0
2 years ago
Look at picture for question and answer
Sonja [21]
1. C

2. A

Hope this helped, enjoy your day.
4 0
3 years ago
What is 6.729 x 8.3 (show ur work)
katen-ka-za [31]

Answer:92,817,765

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Starting with the ones digit of the bottom number, the multiplier, multiply it by the last digit in the top number

Write the answer below the equals line

If that answer is greater than nine, write the ones place as the answer and carry the tens digit

Proceed right to left. Multiply the ones digit of the bottom number to the next digit to the left in the top number. If you carried a digit, add it to the result and write the answer below the equals line. If you need to carry again, do so.

When you've multiplied the ones digit by every digit in the top number, move to the tens digit in the bottom number.

Multiply as above, but this time write your answers in a new row, shifted one digit place to the left.

When you finish multiplying, draw another answer line below your last row of answer numbers.

Use long addition to add your number columns from right to left, carrying as you normally do for long addition.

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Long multiplication with decimals using the standard algorithm has a few simple additional rules to follow.

Count the total number of decimal places contained in both the multiplicand and the multiplier.

Ignore the decimals and right align the numbers one on top of the other as if they were integers

Multiply the numbers using long multiplication.

Insert a decimal point in the product so it has the same number of decimal places equal to the total from step 1.

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