Answer:
698 fishes
Step-by-step explanation:
Generally, we can represent an exponential growth function as;
y = a•(1 + r)^t
originally, there were 3 fishes
The original value in this case means a = 3
After 6 weeks, there were 31
31 in this case is y
r is the increase percentage or rate
t is the time
So, we have it that;
31 = 3•(1 + r)^6
31/3 = (1 + r)^6
10.33 = (1 + r)^6
ln 10.33 = 6 ln (1 + r)
ln 10.33/6 = ln (1 + r)
e^0.3892 = (1 + r)
1 + r = 1.476
r = 1.476-1
r = 0.476 or 47.6%
So the growth percentage or rate is 47.6%
For 14 weeks, we simply have the value of t as 14;
So ;
y = 3•(1 + 0.476)^14
y = 3(1.476)^14
y = 698 fishes
Answer:
Step-by-step explanation:
In a deck of cart, we have:
a = 4 (aces)
t = 4 (three)
j = 4 (jacks)
And the total number of cards in the deck is
n = 52
So, the probability of drawing an ace as first cart is:
At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is
Therefore, the probability of drawing a three at the 2nd draw is
Then, at the third draw, the previous 2 cards are not replaced, so there are now
cards in the deck. So, the probability of drawing a jack is
Therefore, the total probability of drawing an ace, a three and then a jack is:
Answer:
Two systems of equations are equivalent if they have the same solution(s).
f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
Answer:
Therefore $98 is be charged a bus containing 30 people.
Step-by-step explanation:
Given that,
A state park charges an entrance fee based on the number of people in vehicle.
Let the entry fee for the vehicle be E and entry fee for each person be x.
Then
C= E+(P×x)
C= Total charge in $
E= entry fee for a vehicle
P=No. of person
x= Entry charge per person.
Given A car containing 2 people charged $14
C=$14, P=2
∴14= E+(2× x)
⇒E+2x=14.....(1)
Again A car containing 4 people charged $20
C=$20, P=4
∴20= E+(4× x)
⇒E+4x=20.....(2)
Subtract (1) from (2), we get
E+4x-(E+2x)= 20-14
⇒E+4x-E-2x=6
⇒2x=6
⇒x=3
Putting the value of x in equation (1)
E+(2×3)=14
⇒E=14-6
⇒E=8
Therefore E=$8 and x=$3
Next we check whether our assumption is correct or wrong. Putting the value of E and x for third case
Here P= 8
Therefore C= E+(P×x)
= 8+(8× 3)
=8+24
=$32
Therefore our assumption is correct.
Now C=? , P= 30
The charged for the 30 people is
C= $[8+(30×3)]
=$[8+90]
=$98
Therefore $98 is be charged a bus containing 30 people.
