A1=2
a2=-8
a3=32
a4=-128
a2/a1=(-8)/2→a2/a1=-4
a3/a2=32/(-8)→a3/a2=-4
a4/a3=(-128)/32→a4/a3=-4
a2/a1=a3/a2=a4/a3=r=-4
an=a1*r^(n-1)
an=2*(-4)^(n-1)
The explicit rule for the nth term of the given sequence is an=2*(-4)^(n-1)
Answer:
y = -2x - 3
Step-by-step explanation:
-solve for y: y = 1/2x + 2
-perpendicular equals opposite slope: -2
-plug in the point: (1) = -2(-2) + b
1 = 4 + b
b = -3
put it all together: y = -2x - 3
X+2.5 because you dont know her height of last year which would give you the variable X and this year she grew 2.5 inches which would make the equation X+2.5
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Answer:
4π mi²
Step-by-step explanation:
s = (∅/360) * πr²
s = (135/360) * π(4²)
s = (135/360)(16) * π
s = 4π mi²
Well, parallel lines have the same exact slope, so hmmm what's the slope of the one that runs through <span>(0, −3) and (2, 3)?
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so, we're really looking for a line whose slope is 3, and runs through -1, -1
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![\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -1 &,& -1~) \end{array} \\\\\\ % slope = m slope = m\implies 3 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=3[x-(-1)] \\\\\\ y+1=3(x+1)](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%20-1%20%26%2C%26%20-1~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%20m%5Cimplies%203%0A%5C%5C%5C%5C%5C%5C%0A%25%20point-slope%20intercept%0A%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-%28-1%29%3D3%5Bx-%28-1%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay%2B1%3D3%28x%2B1%29)
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