Using the <u>normal distribution and the central limit theorem</u>, it is found that there is an approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.
Normal Probability Distribution
In a normal distribution with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, for n instances of a normal variable, the mean is
while the standard deviation is 
.
In this problem:
- Mean of 4 candies, hence
. - Standard deviation of 1.5 candies, hence
. - She visited 35 houses, hence
The probability is the <u>p-value of Z when X = 122</u>, hence:
By the Central Limit Theorem
has a p-value of 0.
Approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.
A similar problem is given at brainly.com/question/24663213
Answer:
5 seconds
Step-by-step explanation:
The relationship between "d" and "the ground" is not described. If we assume that "d" is distance above the ground, then the rock will hit the ground when d=0. This gives rise to the quadratic equation ...
-t^2 +4t +5 = 0
-(t -5)(t +1) = 0
t = 5 or t = -1 are solutions. Only the positive solution is useful.
The rock will hit the ground after 5 seconds.
Answer:
$113.40
Step-by-step explanation:
The dress is $180 subtracted by 30% ($54) and is now $126
$126 - 10% which is $12.60 and is now $113.40
Answer:
1
Step-by-step explanation:
All are divisible by 1.
Answer:
<h2>SA = 5645cm²</h2>
Step-by-step explanation:
We have three pairs of congruent rectangles
9cm × 4m; 9cm × 5cm and 4m × 5cm
We know 1m = 100cm, therefore 4m = 400cm
The formula of an area of a rectangle l × w:
A = l · w
Substitute:
A₁ = 9cm · 4m = 9cm · 400cm = 3600cm²
A₂ = 9cm · 5cm = 45cm²
A₃ = 4m · 5cm = 400cm · 5cm = 2000cm²
Calculate the surface area:
SA = A₁ + A₂ + A₃
SA = 3600cm² + 45cm² + 2000cm² = 5645cm²
