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Lubov Fominskaja [6]
3 years ago
11

29. You drop a handball from a height of 1 meter. Each curved path has 64% of

Mathematics
1 answer:
Flura [38]3 years ago
3 0
I think it’s A sorry if I’m wrong
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Daniel runs 40/5 miles in 124/₁ minutes. What is the unit rate in terms of miles per minute? What the answer:
sasho [114]

Using the given information, the unit rate is 0.0645 miles/minute

<h3>Calculating rate </h3>

From the question, we are to determine the unit rate

From the given information,

Daniel runs 40/5 miles in 124 minutes

That is,

Distance = 40/5 miles = 8 miles  

Time = 124 minutes

Using the formula,

Rate = Distance / Time

Rate = 8 miles / 124 minutes

Rate = 0.0645 miles/minute

Hence, the unit rate is 0.0645 miles/minute

Learn more on Calculating rate here: brainly.com/question/1090517

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3 0
2 years ago
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When an elderly man passed away, he had left each of his 4 children 25% of his estate If he had $72,000, how much did each child
anzhelika [568]
Dividing $72,000 by 4, each child received $18,000
6 0
3 years ago
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Multiply (2x^2-3x+5)(x^2+4x+1)
DochEvi [55]

Answer:

2x^2-12x+5

Step-by-step explanation:

(2x^2-3x+5)(x^2+4x+1)\\(2x^2-12x+5)

3 0
3 years ago
Can someone give me the answers to this or how to find the answers to it?
faltersainse [42]

the discriminant formula is b^2-4ac

so plug the values from each equation into the formula and solve, the result is the value of the discriminant

if the number is negative, there are no real roots/x-int

if it is 0 there is one real root/x-intercepts

if it is positive it has 2 real roots/x-int

and to find the actual solutions you have to plug the values into the quadratic formula

6 0
4 years ago
in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok
grandymaker [24]

Answer:

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

\hat p=0.849 estimated proportion of adults were no longer smoking after one month

p_o=0.80 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:  

Null hypothesis:p=0.8  

Alternative hypothesis:p \neq 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

6 0
4 years ago
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