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Ray Of Light [21]
3 years ago
12

Which fingers should you use to type the reach keys?

Computers and Technology
1 answer:
Nimfa-mama [501]3 years ago
3 0
Thumbs is the answer
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A security policy is a
777dan777 [17]

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D: set of rules based on standards and guidelines

Explanation:

3 0
4 years ago
Haniyah drew a beautiful pencil sketch of a scenery. Her computer teacher asked her to convert it into a digital form and post i
Aleksandr-060686 [28]

Scanner.

<em> </em>A <em>scanner</em> is an input device that scans documents such as photographs and pages of text, when a document is scanned, it is converted into a digital format.

4 0
3 years ago
The command button to protect a document is part of the​.
Arlecino [84]

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C file tab

Explanation:

hope this helps

7 0
4 years ago
Why are new versions of applications packages released often ​
stellarik [79]

Answer:

The answer is "new version of application provides more easy to use".

Explanation:

  • In computer science, an application is a program, that is installed on the computer. There are many types of application software, that are "gaming software, working software, programming software, etc." At the end of time users want some new things in software to know users need programmer developed new versions of the software.
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5 0
3 years ago
Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a
kirill115 [55]

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = \frac{CPI*Instruction Count}{ClockRate}

a)

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

b)

for system B CPU time is =\frac{2.5*100,000}{750*10^6}

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = =\frac{2.5*Instruction}{750*10^6}

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

3 0
3 years ago
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